Answer: Center: (0,0)
Vertices: ( √3 , 0 ) , ( − √3 , 0 )
Foci: ( √6 , 0 ) , ( − √6 , 0 )
Eccentricity: √2
Focal Parameter: √6/2
Asymptotes: y = x , y = − x
How to: Rewrite in vertex form and use this form to find the vertex ( h , k ) .
Have a great day and stay safe !
We’re going to use the formula for area of a rectangle, which is length x width. We are also going to use the formula for area of a triangle which is 1/2 x base x height.
Let’s start with the rectangle under the triangle ends of the roof. They are 11mm wide, 10mm high, and there are two of them.
11 x 10 x 2 = 220
Then the other sides that are 16 x 10. There are 2 of them.
16 x 10 x 2 = 320
Then the rectangular pieces of roof, 9.7 x 16, and there are 2 of them.
9.7 x 16 x 2 = 310.4
Lastly, the triangle pieces of roof. (1/2)(base)(height), but there are 2 of them
1/2 x 11 x 8 x 2 = 88
Add up all the parts:
220 + 320 + 310.4 + 88 = 938.4 mm
Answer: C
cosA=AC/AB
sinB=AC/AB
hence cosA=sinB
You could use a calculator, or do mental math.
<span>0*60=2,400 ft^2 is the area of the pool.
(40+2x)(60+2x)=2*2,400
2400+120x+80x+4x^2=4,800
4x^2+200x+2,400-4,800=0
4x^2+200x-2,400=0
4(x^2+50x-600)=0
</span><span>4(x-10)(x+60)=0
x-10=0
x=10 ans. for the width of the patio.
Proof:
(40+2*10)(60+2*10)=2*2,400
(40+20)(60+20)=4,800
60*80=4,800
4,800=4,800</span>
