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alexira [117]
3 years ago
9

Find the approximate area of the shaded part of the circle. Use 3.14 for π

Mathematics
1 answer:
natta225 [31]3 years ago
6 0
Its c i use the calcuatior
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6.) -2x + y = -1<br><br> X Y<br> -4<br> -3<br> -2<br> 1<br> 0
MrRa [10]

Answer:

Step-by-step explanation:

i ASSUME THE QUESTION IS TO DETERMINE Y?  

Rearrange the equation  to y = 2x - 1 and solve for each value of x

<u>X</u>  <u>Y</u>

-4  -9

-3  -7

-2  -5

1   1

0  -1

7 0
2 years ago
Which of the following sets could be the sides of a right triangle?
MArishka [77]
In a right triangle the sum of the squares of the lengths of two shorter sides is equal to the square of the length of the longest side.

a.
2^2+3^2=(\sqrt{13})^2 \\&#10;4+9=13 \\&#10;13=13 \\ true

b.
2^2+2^2=4^2 \\&#10;4+4=16 \\&#10;8=16 \\&#10;not \ true

c.
1^2+(\sqrt{3})^2=2^2 \\&#10;1+3=4 \\&#10;4=4 \\&#10;true

The answer is A and C.
5 0
3 years ago
Read 2 more answers
Drag the numbers to create three ratios that are equivalent to 4:12.
matrenka [14]
First blank is 60 second blank is 12 third blank is 2
6 0
3 years ago
Flying against the wind, a jet travels 4400mi in 8 hours. Flying with the wind, the same jet travels 5820mi in 6 hours. What is
Viefleur [7K]
Let J = rate of jet in still airLet W = rate of wind Distance formula:  d = rt   /   r = d/t Flying against the wind the jet flies at a rate of  J - W = 1860 miles/3 hours = 620 miles per hourFlying with the wind the jet flies at a rate of J+W = 9180 miles/9 hours = 1020 miles per hour The average of these 2 rate is the speed of the jet in still air J = (620+1020)/2 = 820 miles per hour J - W = 620  

820 - W = 620
W = 820 - 620 = 200 miles per hour The jet in still air flies at a rate of 820 mph(miles per hour)The wind speed is 200 mph(miles per hour)
3 0
3 years ago
What is the solution for x in the equation?<br> 9x - 20 - 4x = 40
yan [13]

Answer:

Step-by-step explanation:

X=12

4 0
3 years ago
Read 2 more answers
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