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Gre4nikov [31]
3 years ago
13

Without the wind, a plane would fly due east at a rate of 150 mph. The wind is blowing southeast at a rate of 50 mph. The wind i

s blowing at a 45 angle from due east. What is the actual speed of the plane with the wind?
Mathematics
1 answer:
ch4aika [34]3 years ago
8 0
The actual speed of the plane with the wind:
v² = ( 150 + 50 · cos 45°)² + ( 50 · sin 45°)²
v² = ( 150 + 35.355 )² + 35.355²
v² = 34,356.467 + 1,249.976
v = √35,606.452
v = 188.7 mph
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Pls help me this is 7th grade math
Ymorist [56]

Answer:

118 degrees

Step-by-step explanation:

180-62 = 118

8 0
3 years ago
What is the area of this irregular figure knowing that the formula for the area of a rectangle is l x w.
Lubov Fominskaja [6]

9514 1404 393

Answer:

  42 cm²

Step-by-step explanation:

The attachment shows a couple of ways the figure can be considered.

a) Left and Right rectangles that are 5 cm high and 3 cm wide, together with a central rectangle that is 3 cm high and 4 cm wide. Then the total area is ...

  5×3 + 3×4 + 5×3 = 15 + 12 + 15 = 42 . . . . cm²

__

b) An enclosing rectangle that is 5 cm high and 10 cm wide with a cut-out that is 2 cm high and 4 cm wide. Then the total area is ...

  5×10 -2×4 = 50 -8 = 42 . . . . cm²

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The area of the irregular figure is 42 cm².

3 0
3 years ago
Angle θ is in standard position. if sin(θ) = − 1 3 , and π < θ < 3π 2 , find cos(θ).
kramer

The value of the angle θ is 160.52° then the value of the cosine will be negative 0.9428.

<h3>What is trigonometry?</h3>

Trigonometry deals with the relationship between the sides and angles of a right-angle triangle.

Angle θ is in standard position.

If sin(θ) = − 1/3 , and π < θ < 3π/2

Then the angle will be

\theta = \sin ^{-1}\dfrac{-1}{3}\\\\\theta = -19.47

Then add 180 degrees, then we have

\theta = -19.47 + 180\\\\\theta = 160.52

Then the value of the cosine will be

\cos 160.52^o=-0.9428

More about the trigonometry link is given below.

brainly.com/question/22698523

7 0
3 years ago
Read 2 more answers
83 random samples were selected from a normally distributed population and were found to have a mean of 32.1 and a standard devi
arlik [135]

Answer:

\frac{(82)(2.4)^2}{104.139} \leq \sigma^2 \leq \frac{(82)(2.4)^2}{62.132}

4.525 \leq \sigma^2 \leq 7.602

Now we just take square root on both sides of the interval and we got:

2.127 \leq \sigma \leq 2.757

Step-by-step explanation:

Information given

\bar X=32.1 represent the sample mean

\mu population mean (variable of interest)

s=2.4 represent the sample standard deviation

n=83 represent the sample size  

Confidence interval

The confidence interval for the population variance is given by the following formula:

\frac{(n-1)s^2}{\chi^2_{\alpha/2}} \leq \sigma^2 \leq \frac{(n-1)s^2}{\chi^2_{1-\alpha/2}}

The degrees of freedom given by:

df=n-1=8-1=7

The confidence level is 0.90 or 90%, the value of \alpha=0.1 and \alpha/2 =0.05, and we can use excel, a calculator or a table to find the critical values.  

The excel commands would be: "=CHISQ.INV(0.05,82)" "=CHISQ.INV(0.95,82)". so for this case the critical values are:

\chi^2_{\alpha/2}=104.139

\chi^2_{1- \alpha/2}=62.132

The confidence interval is given by:

\frac{(82)(2.4)^2}{104.139} \leq \sigma^2 \leq \frac{(82)(2.4)^2}{62.132}

4.525 \leq \sigma^2 \leq 7.602

Now we just take square root on both sides of the interval and we got:

2.127 \leq \sigma \leq 2.757

5 0
3 years ago
In to see the<br><br> 2x+y=20<br><br> 6x 5y = 12
Andre45 [30]

Answer:

1: x = 10 − \frac{y}{2}

y = 20 − 2 x

2: x = \frac{25}{y}

y = \frac{25}{x}

Step-by-step explanation:

6 0
3 years ago
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