Answer:
(2x+11)x (2x-11)
Step-by-step explanation:
The distance formula is: d = sqrt( (x2 - x1)2 + (y2 - y1)2 )
For this problem, let (-5, -4) be the "first" point, so x1 = -5 and y2 = -4
and let (-6, 4) be the "second" point, so x2 = -6 and y2 = 4.
Then: d = sqrt( (-6 - -5)2 + (4 - -4)2 ) = sqrt( (-1)2 + (8)2 ) = sqrt( 1 + 64 ) = sqrt( 65)
The distance formula is just the Pythagorean Theorem applied to an x-y graph.
You would get the same final answer if you let (-5, -4) be the second point and (-6, 4) be the first point.
<h2><em>y
2
+
6
y
−
16
=
(
y
+
8
)
(
y
−
2
)
</em></h2><h2 /><h2><em>Explanation:
</em></h2><h2><em>Note that in general:
</em></h2><h2 /><h2><em>(
y
+
a
)
(y
−
b
)
=
y
2
+
(
a
−
b
)
y
−
a
b
</em></h2><h2 /><h2><em>So we want to find a pair of factors a and b of 16 which differ by 6
. </em></h2><h2><em>The pair 8
,
2 works in that 8−
2
=
6 and 8
⋅
2=
16
.
</em></h2><h2 /><h2><em>Hence:
</em></h2><h2><em>
y
2
+
6
y
−
16
=
(
y+
8
)
(
y
−
2
)</em></h2><h2><em>y=2,-8</em></h2>
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is symmetric if 
. We have
is indeed symmetric.