Ok so 5x20 is 100 and 3x20 is 60 then add 3 is 63 apps that she downloaded then 100-63 is 37 apps that she still has space for.
Answer: The required solution is 
Step-by-step explanation:
We are given to solve the following differential equation :
where k is a constant and the equation satisfies the conditions y(0) = 50, y(5) = 100.
From equation (i), we have
Integrating both sides, we get
![\int\dfrac{dy}{y}=\int kdt\\\\\Rightarrow \log y=kt+c~~~~~~[\textup{c is a constant of integration}]\\\\\Rightarrow y=e^{kt+c}\\\\\Rightarrow y=ae^{kt}~~~~[\textup{where }a=e^c\textup{ is another constant}]](https://tex.z-dn.net/?f=%5Cint%5Cdfrac%7Bdy%7D%7By%7D%3D%5Cint%20kdt%5C%5C%5C%5C%5CRightarrow%20%5Clog%20y%3Dkt%2Bc~~~~~~%5B%5Ctextup%7Bc%20is%20a%20constant%20of%20integration%7D%5D%5C%5C%5C%5C%5CRightarrow%20y%3De%5E%7Bkt%2Bc%7D%5C%5C%5C%5C%5CRightarrow%20y%3Dae%5E%7Bkt%7D~~~~%5B%5Ctextup%7Bwhere%20%7Da%3De%5Ec%5Ctextup%7B%20is%20another%20constant%7D%5D)
Also, the conditions are
and
Thus, the required solution is
Answer:
Distributive Property of Multiplication
Answer:
x = 1 and y = 2
Step-by-step explanation:
Let apples are represented by x
and let oranges are represented by y
You purchase 5 pounds of apples and 2 pounds of oranges for $9. This line in equation format can be written as:
5x + 2y = 9
Your friend purchases 5 pounds of apples and 6 pounds of oranges for $17.
This line in equation format can be written as:
5x + 6y = 17
Now we have two equations:
5x + 2y = 9 -> eq (i)
5x + 6y = 17 -> eq(ii)
We can solve these equations to find the value of x and y.
Subtracting eq(i) from eq(ii)
5x + 6y = 17
5x + 2y = 9
- - -
_________
0+4y= 8
=> 4y = 8
y= 8/4
y = 2
Now, putting value of y in eq (i)
5x + 2y = 9
5x +2(2) = 9
5x +4 = 9
5x = 9-4
5x = 5
x = 1
so, x = 1 and y = 2
Not to seem rude, but you might have better luck in Business. Unless someone here know accounting lol
