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2 years ago

Two functions are shown at the top.

Mathematics

1 answer:

Rina8888 [55]2 years ago

4 0

Answer:

Step-by-step explanation:

Rate of change is the slope

Function A:

Slope = change in y/Change in x

= (9-3)/(3-0) = 6/3 = 2

Function B:

Clearly the slope is 3

(y = mx + c, m is the slope)

Rate of change of B is more than A

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6. Benny earns $12.00 per hour as a lifeguard. He earns a bonus of $75.00

Vesna [10]

Answer:

75+12h ≥ 399

He must work at least 27 hours

Step-by-step explanation:

How much does benny earn

He makes 75 for the course plus 12 dollars an hour

75+ 12h

This must be at least 399

75+12h ≥ 399

Subtract 75 from each side

75-75+12h ≥ 399-75

12h ≥ 324

Divide each side by 12

12h/12 ≥ 324/12

h ≥ 27

He must work at least 27 hour

3 0

2 years ago

Read 2 more answers

PART 1

Sloan [31]

the answer has to be C

4 0

3 years ago

27 + 71 = 98 + 1 - ______. What should come in the box to make the above number sentence true?

Andreas93 [3]

Answer:

Step-by-step explanation:

Read the article and review the phases of mitosis.

Mitosis

What are the four phases of mitosis?

prophase

metaphase

anaphase

telophase

cytokinesis

8 0

1 year ago

Need the answer explained

Sever21 [200]

Answer:

it's very simple maybe it's in ur book?

4 0

2 years ago

If 14 g of a radioactive substance are present initially and 7 yr later only 7 g remain, how much of the substance will be pres

Delvig [45]

Answer:

2.60 gr

Step-by-step explanation:

We need to consider the function $P(t) = P_oe^{kt}$ where Po is the initial substance k is the rate of decay and t is the time

We know that $P_o = 14$ and at the 7 th year P(t) is 7

This means

$7 = 14e^{7k}$

We solve for k

$\frac{7}{14} = e^{7k}\\\\\ln (\frac{7}{14}) = 7k\\\\k = \frac{\ln (7/14)}{7} = -0.099\\\\Then \ P(t) = 14e^{-0.099t}\\\\Now \ we \ take \ t = 17\\\\P(17) = 14e^{(-0.099)(17)} = 2.60$

8 0

3 years ago