Answer:
The price of an advance ticket = 25$
The price of a same day ticket = 20 $
Step-by-step explanation:
Given there are two types of tickets:
(i) Advance, call it A and
(ii) Same - day, call it S.
Now it is also given that the combined cost of them is 45$.
⇒ A + S = 45$ .....(1)
Also given is that 30 Advance tickets and 20 same day tickets are sold for a total of 1150 $. Mathematically representing this would be:
30 A + 20 S = 1150 $ .....(2)
Now we have to solve Equations (1) and (2) to get values for A and S.
To do that multiply (1) by 30 and subtract (1) and (2).
We will get S = 20. Substitute this in (1). We get A = 25.
Thus, we say the cost of an Advance ticket is 25$ and
The cost of a same day ticket is 20$.
