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Irina-Kira [14]
3 years ago
12

You are given the function C(x)=−4x2+4x+3 Find C(−1). Provide your answer below: C(−1)=

Mathematics
2 answers:
Varvara68 [4.7K]3 years ago
7 0

Answer:

C(-1)= -5

Step-by-step explanation:

This question asks us to find C(-1). We know what C(x) is, it is:

C(x)=-4x^{2} +4x+3

Therefore, we must substitute -1 in for every x to find C(-1).

C(-1)=-4(-1)^{2} +4(-1)+3

Now, solve according to PEMDAS: Parentheses, Exponents, Multiplication, Division, Addition, Subtraction.

First, evaluate the exponent.

-1^2=-1*-1=1

C(-1)=-4(1) +4(-1)+3

Next, multiply -4 and 1.

C(-1)=-4+4(-1)+3

Multiply 4 and -1 again.

C(-1)=-4+ -4 + 3

Add the numbers together.

C(-1)=-8+3

C(-1)=-5

Sedaia [141]3 years ago
3 0

Hey there! :)

Answer:

C(-1) = -5.

Step-by-step explanation:

C(x) = -4x² + 4x + 3

Plug in -1 for x to solve for C(-1):

C(-1) = -4(-1)² + 4(-1) + 3

Simplify:

C(-1) = -4 + (-4) + 3

C(-1) = -5

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Answer:

If the numbers were the same, they'd both be 61

So, try 60 and 62.

x + x+2 = 122

2x = 120

x = 60

Hope that helps!

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2 years ago
On a unit circle, the vertical distance from the x-axis to a point on the perimeter of the circle is twice the horizontal distan
swat32

Check the picture below.

since the vertical distance, namely the y-coordinate, is twice as much as the horizontal, then if the horizontal is "x", the vertical one must be 2x.

let's find the hypotenuse first.

\bf \textit{using the pythagorean theorem} \\\\ c^2=a^2+b^2\implies c=\sqrt{a^2+b^2} \qquad \begin{cases} c=hypotenuse\\ a=\stackrel{adjacent}{x}\\ b=\stackrel{opposite}{2x}\\ \end{cases} \\\\\\ c=\sqrt{x^2+(2x)^2}\implies c=\sqrt{x^2+4x^2}\implies c=\sqrt{5x^2}\implies c=x\sqrt{5} \\\\[-0.35em] ~\dotfill

\bf sin(\theta )=\cfrac{\stackrel{opposite}{2~~\begin{matrix} x \\[-0.7em]\cline{1-1}\\[-5pt]\end{matrix}~~ }}{\stackrel{hypotenuse}{~~\begin{matrix} x \\[-0.7em]\cline{1-1}\\[-5pt]\end{matrix}~~ \sqrt{5}}}\implies \stackrel{\textit{and rationalizing the denominator}~\hfill }{\cfrac{2}{\sqrt{5}}\cdot \cfrac{\sqrt{5}}{\sqrt{5}}\implies \cfrac{2\sqrt{5}}{(\sqrt{5})^2}\implies \cfrac{2\sqrt{5}}{5}}

5 0
3 years ago
If the product of two number is 10 and the sum is 7 ,then the longest of the two number is​
irinina [24]

Answer:

5 units

Step-by-step explanation:

Step one:

Given data

Le the first number be x

and the second number be y

So

x*y= 10-----------------1

and

x+y= 7-----------------2

from eqn 1

x= 10/y

put x= 10/y in eqn 2

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cross multiply we have

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rearrange

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the factors of the quadratic expression are

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The longest side is 5 units

3 0
3 years ago
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