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gayaneshka [121]
3 years ago
8

Please help

Mathematics
1 answer:
ASHA 777 [7]3 years ago
5 0

Answer:

(-6,4)

Step-by-step explanation:

The equations are:

x^2+4y^2=100\\4y-x^2=-20

Solving for x^2 of the 2nd equation and putting that in place of x^2 in the 2nd equation we have:

4y-x^2=-20\\x^2=4y+20\\-------\\x^2+4y^2=100\\4y+20+4y^2=100

Now we can solve for y:

4y+20+4y^2=100\\4y^2+4y-80=0\\y^2+y-20=0\\(y+5)(y-4)=0\\y=4,-5

So plugging in y = 4 into an equation and solving for x, we have:

x^2=4y+20\\x=+-\sqrt{4y+20} \\x=+-\sqrt{4(4)+20} \\x=+-\sqrt{36} \\x=6,-6

So y = 4 corresponds to x = 6 & x = -6

The pairs would be

(6,4) & (-6,4)

<u><em>we see that (-6,4) falls in the 2nd quadrant, thus this is the solution we are looking for.</em></u>

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368.54 = ( _ x 100) + ( _ x 10) + ( _ x 1/10) + ( _ x 1/100)
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Answer:

368.54 = 3*100 + 6.8*10 +5*1/10 + 4*100

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Given

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<em><u>Solved</u></em>

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