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gayaneshka [121]
3 years ago
8

Please help

Mathematics
1 answer:
ASHA 777 [7]3 years ago
5 0

Answer:

(-6,4)

Step-by-step explanation:

The equations are:

x^2+4y^2=100\\4y-x^2=-20

Solving for x^2 of the 2nd equation and putting that in place of x^2 in the 2nd equation we have:

4y-x^2=-20\\x^2=4y+20\\-------\\x^2+4y^2=100\\4y+20+4y^2=100

Now we can solve for y:

4y+20+4y^2=100\\4y^2+4y-80=0\\y^2+y-20=0\\(y+5)(y-4)=0\\y=4,-5

So plugging in y = 4 into an equation and solving for x, we have:

x^2=4y+20\\x=+-\sqrt{4y+20} \\x=+-\sqrt{4(4)+20} \\x=+-\sqrt{36} \\x=6,-6

So y = 4 corresponds to x = 6 & x = -6

The pairs would be

(6,4) & (-6,4)

<u><em>we see that (-6,4) falls in the 2nd quadrant, thus this is the solution we are looking for.</em></u>

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Aleks [24]
<h3>Answer:  sometimes true</h3>

=======================================================

Explanation:

The plane P can be thought of a perfectly flat ground. Now imagine a flag pole which represents line GH. If AB is drawn in chalk on the pavement, and this line AB intersects the base of the flagpole, then we've made AB and GH intersect. However, this example shows that GH is <u>not</u> on the plane P.

Is it possible to have GH be in the the plane? Yes. We could easily draw another chalk line on the ground to have it intersect AB somewhere. But as the previous paragraph says, it's also possible that GH is not in the plane.

Therefore, the statement is sometimes true

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3 years ago
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2 years ago
Sean is taking drivers ed. And the instructor asked him to stay within 2 miles of the posted speed limits. The current speed lim
Aleonysh [2.5K]

Answer:

{x| 43 ≤ x ≤ 47} where x = Sean's speed (in mph)

Step-by-step explanation:

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So, the maximum speed which Sean can reach is, (45 + 2) mph

                                                                                   =47 mph

and,  the minimum speed which Sean can reach is, (45 - 2) mph

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3 0
3 years ago
HELP ME AND PLEASE HURRY
Damm [24]
The answer is sometimes true
8 0
3 years ago
Which transformations could have been used to create A'B'C'? Choose all that apply.
Eduardwww [97]

The correct transformation is a rotation of 180° around the origin followed by a translation of 3 units up and 1 unit to the left.

<h3>Which transformation is used to get A'B'C'?</h3>

To analyze this we can only follow one of the vertices of the triangle.

Let's follow A.

A starts at (3, 4). If we apply a rotation of 180° about the origin, we end up in the third quadrant in the coordinates:

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Now if you look at A', you can see that the coordinates are:

A' = (-4, -1)

To go from (-3, -4) to (-4, -1), we move one unit to the left and 3 units up.

Then the complete transformation is:

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If you want to learn more about transformations:

brainly.com/question/4289712

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