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Lemur [1.5K]
3 years ago
14

Sixty percent of those who attended the soccer game were parents. There were 120 people who attended the soccer game. How many p

arents attended?
40

48

60

72
--------------------------------
During a school assembly, 15 out of 60 students wore orange shirts to show school spirit. What percentage of the students did not wear orange shirts?
Group of answer choices

8%

15%

25%

75%
--------------------------------
The sales tax on groceries was 2%. Karen paid $2.50 in sales tax on the groceries she bought. How much money did Karen spend on groceries before tax?
Group of answer choices

$125

$100

$50

$25
--------------------------------
A club has 100 members.

2/5 of the members worked on the school painting project.
The rest cleaned up a local park.
What percentage cleaned up the park?

Group of answer choices

20%

40%

60%

80%
--------------------------------
At a school, 52 students in 6th grade were on the honor roll. If 28% of the 6th graders were on the honor roll, about how many students are in the 6th grade?
Group of answer choices

186

134

80

67
Mathematics
1 answer:
iren [92.7K]3 years ago
7 0

Answer: 48, 25%, 125 , 60,  80

Step-by-step explanation:

You might be interested in
-6 - 3(2x + 4) = 18what’s the answer
Brrunno [24]

Answer:

x=-6

Step-by-step explanation:

-6-3\left(2x+4\right)=18

Add 6 to both sides:

-6-3\left(2x+4\right)+6=18+6

-3\left(2x+4\right)=24

Divide both sides by -3:

\frac{-3\left(2x+4\right)}{-3}=\frac{24}{-3}

2x+4=-8

Subtract 4 from both sides:

2x+4-4=-8-4

2x=-12

Divide both sides by 2:

\frac{2x}{2}=\frac{-12}{2}

x=-6

7 0
3 years ago
HELP PLEASE<br><br><br> SHOW WORK<br> WILL MARK BRAINLIEST
defon

I've attached a photo of the solution below. Hope it helps!

3 0
2 years ago
WILL GIVE BRAINLIEST ANSWER TO WHOEVER ANSWERS FIRST AND CORRECT PLEASE EXPLAIN WHY YOU ARE CORRECT
Sholpan [36]

Answer:

In a typical kite as shown in picture, it is symmetric around PQ and PQ is perpendicular with RN.

=> Two right triangles PNT and PRT are congruent.

=> angle PRT = angle PNT = 34 deg

=> angle RPT = 90 - angle PRT = 90 - 34 = 56 deg

=> Option A is correct.

Hope this helps!

:)

4 0
3 years ago
Read 2 more answers
At an airport, 76% of recent flights have arrived on time. A sample of 11 flights is studied. Find the probability that no more
I am Lyosha [343]

Answer:

The probability is  P( X \le 4 ) = 0.0054

Step-by-step explanation:

From the question we are told that

   The percentage that are on time is  p =  0.76

   The  sample size is n =  11

   

Generally the percentage that are not on time is

     q =  1- p

     q =  1-  0.76

     q = 0.24

The  probability that no more than 4 of them were on time is mathematically represented as

        P( X \le 4 ) =  P(1 ) +  P(2) + P(3) +  P(4)

=>     P( X \le 4 ) =  \left n } \atop {}} \right.C_1 p^{1}  q^{n- 1} +   \left n } \atop {}} \right.C_2p^{2}  q^{n- 2} +  \left n } \atop {}} \right.C_3 p^{3}  q^{n- 3}  +  \left n } \atop {}} \right.C_4 p^{4}  q^{n- 4}

P( X \le 4 ) =  \left 11 } \atop {}} \right.C_1 p^{1}  q^{11- 1} +   \left 11 } \atop {}} \right.C_2p^{2}  q^{11- 2} +  \left 11 } \atop {}} \right.C_3 p^{3}  q^{11- 3}  +  \left 11 } \atop {}} \right.C_4 p^{4}  q^{11- 4}

P( X \le 4 ) =  \left 11 } \atop {}} \right.C_1 p^{1}  q^{10} +   \left 11 } \atop {}} \right.C_2p^{2}  q^{9} +  \left 11 } \atop {}} \right.C_3 p^{3}  q^{8}  +  \left 11 } \atop {}} \right.C_4 p^{4}  q^{7}

= \frac{11! }{ 10! 1!}  (0.76)^{1}  (0.24)^{10} +   \frac{11!}{9! 2!}  (0.76)^2 (0.24)^{9} + \frac{11!}{8! 3!}  (0.76)^{3}  (0.24)^{8}  + \frac{11!}{7!4!}  (0.76)^{4}  (0.24)^{7}

P( X \le 4 ) = 0.0054

4 0
3 years ago
We have to write this equation 27⅔ in radical notation
ankoles [38]

Answer:

Step-by-step explanation:

6 0
3 years ago
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