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3 years ago

Simplify the expression -3 divided by -2/5.

1 answer:

5 0

You can either convert -3 into a fraction, or convert -2/5 into a decimal so you can solve this.
If you decide to convert -3, into a fraction, it would be -3/1, and you'd have to multiply that by the reciprocal of -2/5.
So, you'd have -3/1(-5/2)=15/2, which can be simplified to 7 1/2.
If you decide to convert -2/5 into a decimal, you would get -0.4. You would then divide -3 by -0.4, which is equal to 7.5.
Both 7.5 and 7 1/2 are correct answers, and if you were to convert 7.5 into a fraction and 7 1/2 into a decimal, you would notice that they are the same number, but in different forms.

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In a causal-comparative study, what is the difference between independent variables and dependent variables? independent variabl

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3 years ago

Solve for x, 0 ≤ x ≤2π (2cosx-1)(2sinx+√3 ) = 0

vladimir1956 [14]

Answer:

x = π/3, x = 5π/3, x = 4π/3

Step-by-step explanation:

Let's split the given equation (2cosx-1)(2sinx+√3 ) = 0 into two parts, and solve each separately. These parts would be 2cos(x) - 1 = 0, and 2sin(x) + √3 = 0.

$2\cos \left(x\right)-1=0,\\2\cos \left(x\right)=1,\\\cos \left(x\right)=\frac{1}{2}$

Remember that the general solutions for cos(x) = 1/2 are x = π/3 + 2πn and x = 5π/3 + 2πn. In this case we are given the interval 0 ≤ x ≤2π, and therefore x = π/3, and x = 5π/3.

Similarly:

$\:2\sin \left(x\right)+\sqrt{3}=0,\\2\sin \left(x\right)=-\sqrt{3},\\\sin \left(x\right)=-\frac{\sqrt{3}}{2}$

The general solutions for sin(x) = - √3/2 are x = 4π/3 + 2πn and x = 5π/3 + 2πn. Therefore x = 4π/3 and x = 5π/3 in this case.

So we have x = π/3, x = 5π/3, and x = 4π/3 as our solutions.

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3 years ago

If a*b means 2a + b , then what is 2*5 ?

NeX [460]

Answer:

Step-by-step explanation:

let a = 2

b = 5

2a + b

Substituting the values,

=> 2(2) + 5

=> 4 + 5

=> 9

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3 years ago

The universal set in this diagram is the set of integers from 1 to 15. place the integers in the correct place in the venn diagr

neonofarm [45]

Answer:

Step-by-step explanation:

Given : universal set in this diagram is the set of integers from 1 to 15.

Solution :

The intersection of odd integer,multiples of 3 and Factors of 15 are 3,15

The intersection of odd integer and Factors of 15 are 1,5

The intersection of odd integer,multiples of 3 is 9

The remaining multiples of 3 are 6,12

The remaining odd integers are 7,11,13

Now the remaining integers are 2,4,8,10,14 and these integers must be placed in the boxes outside the circles Since they does not belong any intersection or odd integer or factor of 15 .

Refer the attached figure for the answer.

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2 years ago

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