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dimaraw [331]
3 years ago
7

How exactly do you do this because my teacher didn't teach me how

Mathematics
1 answer:
mylen [45]3 years ago
6 0
The area is found by base x height

To find the missing height in the first one you divide 147 by 15 3/4 and get 9 1/3. 
To find the missing base in the second one you divide 140 5/8 by 11 1/4 and get 12 1/2.
To find the missing height in the third one you divide 151 3/16 by 10 1/4 and get 14 3/4. 

Make me brainliest ! :)

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Find the value of 2 - 3x when x = 7 PLEASE HELP ME :(
Sergio [31]

Answer:

-19

Step-by-step explanation:

4 0
3 years ago
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What is equivalent decimal for 0.85
Alex_Xolod [135]

Answer:

17/20

Step-by-step explanation:

0.85 = 85/100 = 17/20

The number 0.85 can be written using the fraction 85/100 which is equal to 17/20 when reduced to lowest terms.

5 0
3 years ago
In a random sample of 205 people, 149 said that they watched educational television. Find the 95% confidence interval of the tru
tensa zangetsu [6.8K]

Answer: Given a sample of 200, we are 90% confident that the true proportion of people who watched educational TV is between 72.1% and 81.9%.

Step-by-step explanation:

\frac{154}{200} =0.77

1-0.77=0.23

\sqrt{\frac{(0.77)(0.23)}{200} }=0.049

0.77±0.049< 0.819, 0.721

6 0
3 years ago
The air force reports that the distribution of heights of male pilots is approximately normal, with a mean of 72.6 inches and a
Phantasy [73]

Answer:

Step-by-step explanation:

Given that X -  the distribution of heights of male pilots is approximately normal, with a mean of 72.6 inches and a standard deviation of 2.7 inches.

Height of male pilot = 74.2 inches

We have to find the percentile

X = 74.2

Corresponding Z score = 74.2-72.6 = 1.6

P(X<174.2) = P(Z<1.6) = 0.5-0.4452=0.0548=5.48%

i.e. only 5% are below him in height.

Thus the malepilot is in 5th percentile.

8 0
3 years ago
Find the distance between the two points (-10,3) and (0,27)​
crimeas [40]

Answer:

26 units

Step-by-step explanation:

\boxed{distance \: between \: 2 \: points =  \sqrt{ {(x1 - x2)}^{2} +  {(y1 - y2)}^{2}  } }

Using the formula above,

distance between (-10, 3) and (0, 27)

=  \sqrt{ {( - 10 - 0)}^{2}  +  {(3 - 27)}^{2} }

=  \sqrt{ {10}^{2}  + ( - 24) {}^{2} }

=  \sqrt{100 + 576}

=  \sqrt{676}

= 26 units

5 0
2 years ago
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