Π = 3.14
π = 3.141592653589793
A: Suppose Mr. Moore decides to use 20 seventh graders as the sample. Is this sample a random sample? Explain your reasoning.
Ans: No, because he only chose the seventh graders which is invalid since he wants to have to use the mean height which involves the 6th, 7th and 8th graders.
B: Mr. Moore decides to use a random number generator to select 20 students from the school. Suppose that when choosing 20 students using the random generator on the graphing calculator, Mr. Moore’s sample is all eighth graders. Does that mean the sample is not a random sample? Explain your reasoning.
Ans: No, it is still a random sample. Since he is using a random generator, there is a possibility that the random generator would pick all students from the 8th grade. Unlike the first one, the random generator is not biased towards any grade, it is just a coincidence.
So when solving this you are going to have to solve the equation.
Okay so first thing we need to do is simplify both sides of your equation so:
3x−5=<span>2x+8+x
</span>Simplifying process:
<span><span><span>3x</span>+</span>−5</span>=<span><span><span>2x</span>+8</span>+<span>x
</span></span><span>Combine Like Terms </span>⇒ 3x−5=<span>(2x+x)+(8)
</span><span><span>3x</span>−5</span>=<span><span>3x</span>+<span>8
</span></span><span><span>3x</span>−5</span>=<span><span>3x</span>+<span>8
</span></span>Second thing we are now going to do is s<span>ubtract 3x from both sides<span> so:
</span></span><span><span><span>3x</span>−5</span>−<span>3x</span></span>=<span><span><span>3x</span>+8</span>−<span>3<span>x
</span></span></span><span>−5</span>=<span>8
</span>Final step is to add 5 to both sides:
−5+5=<span>8+5
</span>0=<span>13
</span>The answer to your question is "<span>There are no solutions"</span>
There would be three rows, going to the right. Each row, would be 15 high.
-7 + 4(n-1). Use this and plug in 10 for n, making it
-7 + 4(9)
-7+36
29
