Ok so substitute the values. a=3 b=2 and c=-3
-3^(2)-3(2)^(3)+(-3)^(2)+2(2)^(3)-(-3)^(2)=-9-24+9+16-9=-33+25-9=-42+25=-17
We asked to solve the volume of the cone and we know that the formula for solving the volume is shown below:
V = 1/3*pi*r²*h where "r" for the radius and "h" for the height
We have the given values such as:
r= diameter/2 = 12/2
r= 6 inches
h=6 inches
Solving for the volume:
V= 1/3 *pi*6²*6
V=72pi in³
The answer is the letter "A" 72pi inches³.
<u>False</u>
<em>Like</em><em> </em><em>terms</em><em> </em><em>have the same literal coefficients </em><em> </em><em>but</em><em> </em><em>can have different Numerical Coefficients</em>
Hope this helped you- have a good day bro cya)
320+124+876=1320 grams = 1.32 kg
1.32*$2.99=$3.95
9514 1404 393
Answer:
8
Step-by-step explanation:
The product of segment lengths to the near and far circle intersection points is the same for both "secants". AD is a tangent, so the two intersection points are the same point. This gives ...
AD² = AB·AC
144 = AB(AB +10)
We can add 25 to complete the square.
169 = (AB +5)² . . . write as a square
13 = AB +5 . . . . . . positive square root
8 = AB . . . . . . . . . .subtract 5
