3 years ago

8y=3x solve for y x-y+2g=5g b=ay solve a b-c/3=a solve for b

Mathematics

1 answer:

Llana [10]3 years ago

3 0

I hope I am right. here you go:)

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$g(x)=x+\frac{1}{9}+\frac{2\sqrt{x}}{3}$

Step-by-step explanation:

Given functions: h(x) = (fog)(x) , h(x) = 3√x + 3 and f(x) = 3√x + 2

To find: function g(x)

Consider,

(fog)(x) = h(x)

f( g(x) ) = h(x)

$3\sqrt{g(x)}+2=3\sqrt{x}+3$

$3\sqrt{g(x)}=3\sqrt{x}+1$

$\sqrt{g(x)}=\frac{3\sqrt{x}+1}{3}$

$\sqrt{g(x)}=\sqrt{x}+\frac{1}{3}$

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$g(x)=(\sqrt{x})^2+(\frac{1}{3})^2+2\times\frac{1}{3}\times\sqrt{x}$

$g(x)=x+\frac{1}{9}+\frac{2\sqrt{x}}{3}$

Therefore, $g(x)=x+\frac{1}{9}+\frac{2\sqrt{x}}{3}$

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