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harina [27]
3 years ago
14

What is 5,307,288 rounded the nearest 100,000

Mathematics
1 answer:
IceJOKER [234]3 years ago
7 0
That's easy it is 5,300,000 I think by the way Might be wrong I hurt my eye so yea don't say I am not good at math it is my eye hurting or it can be 5,300,288 
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What’s the Answer to this I got 24 somehow
Bess [88]

Answer:

0

Step-by-step explanation:

So we have the expression:

\frac{2x+y}{xy-2x}

And we want to evaluate it for x=-4 and y=8.

So, substitute:

\frac{2(-4)+(8)}{(-4)(8)-2(-4)}

Multiply:

=\frac{-8+8}{-32+8}

Add:

=\frac{0}{-24}

Evaluate:

=0

So, our answer is 0.

And we're done!

6 0
3 years ago
From point A and B on level ground, the angles of
gladu [14]

Answer:

Step-by-step explanation:

Call T the top

call G the bottom

T G B is a right triangle

37 at B, 90 at G, thus 53 at BTG

TGA is a right triangle

25 at A, 90 at G, thus 65 at ATG

thus 122 at ABT

law of sines:

sin 25 / BT = sin 12/ 57

so BT = 156 meters (first answer)

now angle ABT = 180 - 12 - 25

= 143

so

sin 143 /AT = sin12/57

AT = 164 meters, second answer

4 0
3 years ago
Use the distance to find the distance between the points A (-3,7 and B (-2,5).
Eva8 [605]

Step-by-step explanation:

1 2 3 4 5

wa

6 0
3 years ago
The distance d, in centimeters, that a diving board bends below its resting position when you stand at its end is dependent on y
kaheart [24]

Answer:

d(1) = -3 and d(2)= -28

Step-by-step explanation:

Given that the distance d, in centimeters, that a diving board bends below its resting position when you stand at its end is dependent on your distance x, in meters, from the stabilized point

d(x)=-4x^3+x^2

For finding out the distances for x=1 and x=2

let us substitute 1 and 2 for x

d(1) = -4(1^3)+1^2 = -3

d(2) = -4(2^3)+2^2 \\= -28

d(1) = -3 and d(2)= -28

3 0
3 years ago
find the component equation of the plane which is normal to the vector -2i+5j+k and which contains the point (-10;7;5).​
maksim [4K]

Given:

A plane is normal to the vector = -2i+5j+k

It contains the point (-10,7,5).​

To find:

The component equation of the plane.

Solution:

The equation of plane is

a(x-x_0)+b(y-y_0)+c(z-z_0)=0

Where, (x_0,y_0,z_0) is the point on the plane and \left< a,b,c\right> is normal vector.

Normal vector is -2i+5j+k and plane passes through (-10,7,5). So, the equation of the plane is

-2(x-(-10))+5(y-7)+1(z-5)=0

-2(x+10)+5y-35+z-5=0

-2x-20+5y-35+z-5=0

-2x+5y+z-60=0

-2x+5y+z=60

Therefore, the equation of the plane is -2x+5y+z=60.

4 0
3 years ago
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