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joja [24]
3 years ago
12

The circumference of a circle is 53.38 centimeters. What is the area in square centimeters. Use 3.14 for ×

Mathematics
1 answer:
Alex Ar [27]3 years ago
4 0
Circumference = πD

53.38 = 3.14D

D = 53.38 ÷ 3.14 = 17

Diameter = 17 cm

Radius = Diameter ÷ 2 = 17 ÷ 2 = 8.5 cm

Area = πr² = 3.14 x (8.5)² = 226.87 cm² (nearest hundredth)

Answer: 226.87 cm² 
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Answer:

There are many lines with slopes of 2. When writing them, they simply need to be y = 2x + b, with which b can be any number.

Step-by-step explanation:

We know this because slope intercept form is y = mx + b, in which m is the slope of the equation.

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Mitchell deposits $1,200 in an account that pays 1.5% simple interest. He keeps the money in the account for three years without
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The amount that will be in the account after three years is $1,254.00.

Using this formula

B = P+ ( P x R x T)

Where:

B=Amount ?

P=Principal=$1,200

r=Rate=1.5% or 0.015

T=Time=3 years

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B=$1,200+($1,200×0.015×3)

B=$1,200+$54

B= $1,254.00

Inconclusion the amount that will be in the account after three years is $1,254.00.

Learn more here:

brainly.com/question/20348538

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The expression is 55 * h= m
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Subduction should be added to divergent boundaries
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<h2><u>Answer with explanation</u>:</h2>

Given: In Δ ABC and ΔAEC,

AB=BC and AD=CD

i) In ΔADB and CBD, we have

AD = DC        [given]

AB=BC           [given]

DB= DB           [given]

⇒ ΔADB ≅ΔCDB   [By SSS congruence rule]

⇒ ∠ADB ≅∠CDB       ...(i)           [Corresponding parts of congruent triangles are congruent]

Since AC is a straight line,

∠ADB+∠CDB = 180°   [Linear pair]

⇒∠ADB+∠ADB=180°   [from (i)]

⇒2 ∠ADB=180°  

⇒∠ADB=90°  =∠CDB

Also ∠ADB+∠ADE=180°   [Linear pair]

⇒∠ADE=180°-∠ADB  = 180°-90°

⇒∠ADE=90°, i.e. ∠ADE is a right triangle.

Similarly, ∠CDB+∠CDE=180°

⇒∠CDE=90°

ii) Now, in ΔADE and CDE

AD= CD   [given]

ED=ED   [Common]

∠ADE= ∠CDE = 90°

⇒ΔADE ≅ CDE   [By SAS congruence rule ]

⇒AE=EC   [Corresponding parts of congruent triangles are congruent]

Hence proved.

6 0
3 years ago
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