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shepuryov [24]
3 years ago
8

I need the steps, I had tryed already and I have an answer key; but I do not have tut he steps. I'm also am not in school at thi

s time.

Mathematics
1 answer:
blagie [28]3 years ago
5 0
The answer is C. From the solution in the picture

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Explain how to find 40×50 using mental math
Dennis_Churaev [7]
4*5 is 20
add 2 zeroes to the end because of the two you took out from 40 and 50
40*50=2000
6 0
4 years ago
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How do you write this into a number sentence.<br> 32 1/4 divided by 1/8 =258.
Zigmanuir [339]
\frac{32\frac{1}{4}}{\frac{1}{8}}=258
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4 years ago
PLEASE HELP GEOMETRY
Anastaziya [24]

Answer:

2x=8

x=4

Step-by-step explanation:

4 0
3 years ago
42 - 35 = 8 - 12 + t <br> What does t mean?
inessss [21]
I think t = 11:
42 - 35 = 8 - 12 + t
7 = 8 - 12 + t
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4 0
3 years ago
How do we create a table of values to help us graph linear equations?​
VashaNatasha [74]

Let's say for example you wanted to graph the linear equation y = 2x+5

At minimum, we'll need 2 points to form this line.

To get any point of the form (x,y), we plug in a number for x to find a corresponding number for y.

For example, replace x with 0 to find that...

y = 2x+5\\\\y = 2(0)+5\\\\y = 0+5\\\\y = 5\\\\

Therefore, x = 0 leads to y = 5. So the point (0,5) is on the line.

Then we repeat this process for other x values. Let's try x = 1

y = 2x+5\\\\y = 2(1)+5\\\\y = 2+5\\\\y = 7\\\\

Telling us that (1,7) is also on this line. We have enough to graph this equation. Plot the two points (0,5) and (1,7). Then draw a straight line through them. Extend this line as far as you can to the left and right. The graph is shown below.

We can keep going to get other points like (2,9) and (3,11) and (4,13) and so on. A table is a way to keep track of the xy values.

\begin{array}{|c|c|}\cline{1-2}\text{x} & \text{y}\\ \cline{1-2}0 & 5\\ \cline{1-2}1 & 7\\ \cline{1-2}2 & 9\\ \cline{1-2}3 & 11\\ \cline{1-2}4 & 13\\ \cline{1-2}\end{array}

Each time x goes up by 1, y goes up by 2. This directly ties to the slope of 2/1 = 2.

6 0
3 years ago
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