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Vikki [24]
2 years ago
9

Hey ! Can anyone help me with this please ? Thank you so much .

Mathematics
1 answer:
castortr0y [4]2 years ago
6 0

9514 1404 393

Answer:

  x = 57

Step-by-step explanation:

Where parallel lines are crossed by a transversal, all obtuse angles are congruent and supplementary to all acute angles, which are also congruent.

  x = 180 -123

  x = 57

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you put $3000 in a CD (certificate of deposit) at the promotional rate of 5.6% simple interest. How long will it take to earn $3
Wewaii [24]

Answer:

1 year 9 months

Step-by-step explanation:


6 0
2 years ago
Anyone? Please I need help!!
JulsSmile [24]

Answer:

  the correct choice is marked

Step-by-step explanation:

Let x represent the smaller number. Then the larger number is 8x, and the difference is ...

  8x -x = 280

  7x = 280 . . . . . simplify

  x = 40 . . . . . . divide by 7

The larger number is 8x = 8(40) = 320.

_____

<em>Additional comment</em>

Effectively, we have solved for the multiplier (40) that gives the ratio with 320 on top and a difference between top and bottom of 280:

  \dfrac{8}{1}=\dfrac{8\cdot40}{1\cdot40}=\dfrac{320}{40}

4 0
2 years ago
Which of the following political philosophies is followed by governments using command economies?
ziro4ka [17]
The answer is democracy
3 0
3 years ago
Read 2 more answers
-10y + 9x = -9<br> 10y + 5x = -5
RoseWind [281]
The answer is (-1,0) or x=-1 and y=0 :)
5 0
3 years ago
Find the 63rd term of the arithmetic sequence -1, 5, 11, ...−1,5,11,...
Ugo [173]

Answer:

a_6_3=371

Step-by-step explanation:

we know that

In an <u><em>Arithmetic Sequence</em></u> the difference between one term and the next is a constant and this constant is called the common difference

we have

-1,5,11,...

Let

a_1=-1\\a_2=5\\a_3=11

a_2-a_1=5-(-1)=5+1=6

a_3-a_2=11-5=6

The common difference is d=6

We can write an Arithmetic Sequence as a rule

a_n=a_1+d(n-1)

where

a_n is the nth term                

d is the common difference

a_1 is the first term

n is the number of terms

Find the 63rd term of the arithmetic sequence

we have

n=63\\d=6\\a_1=-1

substitute

a_6_3=-1+6(63-1)

a_6_3=-1+6(62)

a_6_3=-1+372

a_6_3=371

6 0
3 years ago
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