3 years ago

Please help me……………………………………………………………

Mathematics

1 answer:

Irina18 [472]3 years ago

3 0

Hey there! :)

Answer:

x = -6.

Step-by-step explanation:

Given:

$\sqrt[3]{5x-4} = \sqrt[3]{7x + 8}$

Cube both sides:

5x - 4 = 7x + 8

Subtract 5x from both sides:

-4 = 2x + 8

Subtract 8 from both sides:

-12 = 2x

x = -6.

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Which function is a quadratic function? y – 3x2 = 3(x2 + 5) + 1 y2 – 7x = 2(x2 + 6) + 7 y – 2x2 = 6(x3 + 5) – 4 y – 5x = 4(x + 5

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Answer:

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Step-by-step explanation:

The general form of a quadratic function is

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It means, power of y should be 1 and highest power of x should be 2.

In option A,

$y-3x^2=3(x^2+5)+1$

$y-3x^2=3x^2+15+1$

$y=3x^2+16+3x^2$

$y=6x^2+16$

It is a quadratic function.

In option B,

$y^2-7x=2(x^2+6)+7$

Here, power of y is 2. So, it is not be a quadratic function.

In option C,

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Here, highest power of x is 3. So, it is not be a quadratic function.

In option D,

$y-5x=4(x+5)+9$

Here, highest power of x is 1. So, it is not be a quadratic function.

Therefore, the correct option is A.

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