3 years ago

If p(a) = 1/3, p(b) = 2/5, and p(a ∪ b) = 3/5, then p(a ∩ b) =

Mathematics

1 answer:

Mumz [18]3 years ago

8 0

P(a ∪ b) = p(a) + p(b) - p(a ∩ b)
p(a ∩ b) = p(a) + p(b) - p(a ∪ b)
p(a ∩ b) = 1/3 + 2/5 - 3/5
p(a ∩ b) = 2/15

You might be interested in

I need to solve this.

Svetradugi [14.3K]

Answer:

Step-by-step explanation:

What kind of math is this and what grade are you in?

5 0

3 years ago

Read 2 more answers

41 out of 50 women surveyed liked perfume. what percentage of women did NOT like perfume

krok68 [10]

Answer:

18%

Step-by-step explanation:

Long Version: 41/50 = 0.82 and when you move the decimal two places right, you will get 82%. 100%-82%= 18%

Short Version: 9/50 people didn't like perfume. 9/50= 0.18 then you move the decimal two places right and it becomes 18%.

3 0

2 years ago

Read 2 more answers

For the function F(x) = 1/x-2, which of these could be a value of F(x) when xis

dusya [7]

The answer to this question is C

4 0

3 years ago

Please only 2 minutes. this is late now and i need it done NOW. no files i’m so stressed rn

tia_tia [17]

In great east japan a tsunami happened

5 0

2 years ago

How to solve this :') please help

blsea [12.9K]

Answer:

3/2

Step-by-step explanation:

sin(3π/4 - β) = sin(3π/4)cosβ - cos(3π/4)sinπ =

$\sin(\frac{3\pi}{4}-\beta)=\sin(\frac{3\pi}{4})\cos\beta-\cos\frac{3\pi}{4}\sin\beta\\=\frac{1}{\sqrt{2}}\cos\beta-(-\frac{1}{\sqrt{2}})\sin\beta\\\\=\frac{1}{\sqrt{2}}(\cos\beta +\sin\beta)\\\\\sin^2(\frac{3\pi}{4}-\beta)=\frac{1}{2}\cos\beta +\sin\beta)^2=\frac{1}{2}(\cos^2\beta +\sin^2\beta+2\sin\beta\cos\beta\\=\frac{1}{2}(1+\sin2\beta)=\frac{1}{2}(1-\frac{1}{5}) = \frac{2}{5}\\$

Use $\cot^2x=\csc^2x-1=\frac{1}{\sin^2x}-1$

$\cot^2(\frac{3\pi}{4}-\beta)=\frac{1}{\sin^2(\frac{3\pi}{4}-\beta)}-1 = \frac{1}{\frac{2}{5}}-1=\frac{5}{2}-1=\frac{3}{2}$

7 0

2 years ago