If p(a) = 1/3, p(b) = 2/5, and p(a ∪ b) = 3/5, then p(a ∩ b) =

Mathematics

1 answer:

Mumz [18]3 years ago

8 0

P(a ∪ b) = p(a) + p(b) - p(a ∩ b)
p(a ∩ b) = p(a) + p(b) - p(a ∪ b)
p(a ∩ b) = 1/3 + 2/5 - 3/5
p(a ∩ b) = 2/15

You might be interested in

If you join the store membership, all items over $100 will have a flat rate restocking fee of $5. How much money will a member s

dexar [7]

$235, I believe. 240-5=235.

If you found this especially helpful, I'd appreciate if you'd vote me Brainliest for your answer. I want to be able to assist more users one-on-one, as well as to move up in rank! :)

3 0

3 years ago

Which of the f -values satisfy the following inequality?

pickupchik [31]

The answer would be 4.

3 0

3 years ago

The units for the lines of longitude are measured in.

Sladkaya [172]

The unit of measurement for latitude and longitude is called a degree, which is indicated by a small circle to the upper left after a latitude or longitude is given (ex. 90°).

4 0

2 years ago

What is the slope of the line through the points (6,-8)And (3,- 4)

Nina [5.8K]

Answer:

y=(-4/3)x

Step-by-step explanation:

you put the points into this equation to find the slope

(y2-y1)/(x2-x1)

now lets label the points

(6,-8)

x1=6 and y1=-8

(3,-4)

x2=3 and y2=-4

Input into equation

(-4-(-8))/(3-6)=

(-4+8)/(3-6)

4/-3

7 0

3 years ago

the pitch, or frequency, of a vibrating string varies directly with the square root of the tension. if a string vibrates at a fr

Naily [24]

$\bf \qquad \qquad \textit{direct proportional variation}\\\\
\textit{\underline{y} varies directly with \underline{x}}\qquad \qquad y=kx\impliedby 
\begin{array}{llll}
k=constant\ of\\
\qquad variation
\end{array}\\\\
-------------------------------\\\\
\begin{array}{llll}
\stackrel{frequency}{f}\textit{ of a vibrating string varies directly}\\
\qquad \qquad \textit{with the square root of the tension }\stackrel{tension}{t}
\end{array}$

$\bf f=k\sqrt{t}\quad \textit{we also know that }
\begin{cases}
f=300\\
t=8
\end{cases}\implies 300=k\sqrt{8}
\\\\\\
\cfrac{300}{\sqrt{8}}=k\implies \cfrac{300}{\sqrt{2^2\cdot 2}}=k\implies \cfrac{300}{2\sqrt{2}}=k\implies \cfrac{150}{\sqrt{2}}=k
\\\\\\
\textit{and we can \underline{rationalize} it to }\cfrac{150\sqrt{2}}{2}\implies 75\sqrt{2}=k$

$\bf thus\qquad f=\stackrel{k}{75\sqrt{2}}\sqrt{t}\implies \boxed{f=75\sqrt{2t}}\\\\
-------------------------------\\\\
\textit{now, when t = 72, what is \underline{f}?}\qquad f=75\sqrt{2(72)}$

5 0

3 years ago

Read 2 more answers