Answer:
Step-by-step explanation:
Given
Solving (a); Point estimate of mean
To do this, we simply calculate the sample mean
Solving (b); Point estimate of standard deviation
To do this, we simply calculate the sample standard deviation
<em>Note that: The sample mean and the sample standard deviation are the best point estimators for the mean and the standard deviation, respectively.</em>
<em>Hence, the need to solve for sample mean and sample standard deviation</em>
Since the angles sum of △ is 180°,here's the equation:
60°+65°+(8x+7)=180°
8x+7=180°-60°-65°
8x=55-7
x=48/8
x=6
Thus,the answer is x=6
Hope it helps!
Answer: 0.2727272727. However, if you flip the number you get 3.7
5/10=1/2 - if one student are chosen, who plays soccer
4/9 if then the second student are chosen, who plays soccer
1/2*4/9=2/9 the probability that both students play soccer
Answer: The question is incomplete, here is the complete question ;
Let X denote the distance (m) that an animal moves from its birth site to the first territorial vacancy it encounters. Suppose that for banner-tailed kangaroo rats, X has an exponential distribution with parameter ? = 0.01327. (a) What is the probability that the distance is at most 100 m? At most 200 m? Between 100 and 200 m? (Round your answers to four decimal places.
Step-by-step explanation:
- X = denote the distance (m)
- P (X > x) = exp( - 0.01342x)
- Therefore, P (X < = 100) = 1 - P (X > 100) = e-0.01342 X 100 = 0.2613 ; the probability that the distance is at most 100 m
- Similarly, P (X < =200) = e-0.01342 X 200 = 0.0683 ; At most 200 m
- P(100 < X <200) = 0.2613 - 0.0683 = 0.193 ; Between 100 and 200 m