Answer:
y+4=4(x-3)
Step-by-step explanation:
y-y1=m(x-x1)
y-(-4)=4(x-3)
y+4=4(x-3)
Answer:
24:8 which is also just 6:2 or 3:1
Step-by-step explanation:
There are many ways you can write this, and this is what I think hope this helps
Answer: Stephon can buy total 4 chips bag and 2 candy bar
Step-by-step explanation:Given as :
The money which Stephon has in his pocket = $ 12
The cost of one chips bag = $ 2.25
The cost of one candy bar = $ 1.50
The total number of items he can buy = 6
So, Let the number of chips bag he can buy = x
∴ The number of candy bar he can buy = 6 - x
Now, according to question
The number of chips bag×The cost of one chips bag + The number of candy bar×The cost of one candy bar = $ 12
Or, x × $ 2.25 + (6-x) × $ 1.50 = $ 12
Or, x × $ 2.25 + 9 - x × $ 1.50 = $ 12
or, x × $ 0.75 = 12 - 9
or, x = = 4
The number of chips bag he can buy = x = 4
And The number of candy bar he can buy = 6 - x = 6 - 4 = 2
Hence Stephon can buy total 4 chips bag and 2 candy bar .
Well it’s ok I just have no problem I don’t have any time to talk to answer A
Answer and explanation:
The gambler's fallacy is the fallacy of belief that if an event such as a loss occurs more frequently in the past, it is less likely to happen in the future. We assume here that this belief is true, therefore
If she loses, her probability of winning increases =3/4
If she wins, her probability to win is normal =1/2
Given that probability of winning is 1/2
Probability of losing is 1-1/2=1/2
Probability that she wins the tournament is probability that she wins the first two games and loses the last or wins the first game, loses the second and wins the last or loses the first game and wins the last two games or probability that she wins all three games
=1/2*1/2*1/2+1/2*1/2*3/4+1/2*3/4*1/2+1/2*1/2*1/2
=25/48
Probability of winning the tournament if she loses the first game
=1/2*3/4*1/2= 3/16
Note: whenever there is "or" in probability, you add
