Procedure:
1) Integrate the function, from t =0 to t = 60 minutues to obtain the number of liters pumped out in the entire interval, and
2) Substract the result from the initial content of the tank (1000 liters).
Hands on:
Integral of (6 - 6e^-0.13t) dt ]from t =0 to t = 60 min =
= 6t + 6 e^-0.13t / 0.13 = 6t + 46.1538 e^-0.13t ] from t =0 to t = 60 min =
6*60 + 46.1538 e^(-0.13*60) - 0 - 46.1538 = 360 + 0.01891 - 46.1538 = 313.865 liters
2) 1000 liters - 313.865 liters = 613.135 liters
Answer: 613.135 liters
The transformation which is represented is a 180 degree rotation about the origin
Answer:
Millileters
Step-by-step explanation:
If it held 400 liters, it would be a pretty gigantic cup
Answer:
here's the steps
Step-by-step explanation:
first, you need to get x by itself.In order to do that you need to do the opposite to the other side. ex: x5= 1/10; what you would do is divide 1/10 by 5 to get x = 0.5 , 5/10
