Answer:
The ball shall keep rising tills its velocity becomes zero. Let it rise to a height h feet from point of projection.
Step-by-step explanation:
Let us take the point of projection of the ball as origin of the coordinate system, the upward direction as positive and down direction as negative.
Initial velocity u with which the ball is projected upwards = + 120 ft/s
Uniform acceleration a acting on the ball is to acceleration due to gravity = - 32 ft/s²
The ball shall keep rising tills its velocity becomes zero. Let it rise to a height h feet from point of projection.
Using the formula:
v² - u² = 2 a h,
where
u = initial velocity of the ball = +120 ft/s
v = final velocity of the ball at the highest point = 0 ft/s
a = uniform acceleration acting on the ball = -32 ft/s²
h = height attained
Substituting the values we get;
0² - 120² = 2 × (- 32) h
=> h = 120²/2 × 32 = 225 feet
The height of the ball from the ground at its highest point = 225 feet + 12 feet = 237 feet.
Y=-5/3x+1
I hope this helps!
49. 100-36= how many girls in percent
= 64%
64%= 16 girls
64/100=16/x
cross multiply
1600=64x
x=25
Answer:
f(7) = -113
Step-by-step explanation:
Hello!
Substitute 7 for x in the equation.
<h3>Evaluate</h3>
- f(x) = -4x² + 10x + 13
- f(7) = -4(7)² + 10(7) + 13
- f(7) = -4(49) + 70 + 13
- f(7) = -196 + 70 + 13
- f(7) = -113
f(7) is -113.
Answer:
Cómo se vería si estuviera graficado:
2x−y=−2
3x−3y=15
Cómo se vería si lo resolviera graficando:
(−7,−12)
