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pshichka [43]
2 years ago
14

What is the quotient of the fractions below? 1/3 divided by 5/8

Mathematics
1 answer:
svetlana [45]2 years ago
4 0
<h3>Answer:  8/15</h3>

Work Shown:

x = (1/3) divided by (5/8)

x = (1/3) * (8/5)

x = (1*8)/(3*5)

x = 8/15

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Four more than the quotient of a number and 3 is at least 9
Natali [406]
The correct answer is 15

 <span>4 + (x/3) = 9 </span>

<span>(x/3) = 9 - 4 </span>

<span>(x/3) = 5 </span>

<span>x = 15 </span>
7 0
2 years ago
Add or subtract as indicated. reduce to the lowest term. 1 1/3 + 2 1/3
Ann [662]
2 1/3 = 7/3

Both numbers should be improper fractions.

11/3 + 7/3 = 18/3

Now the fractions must be simplified
18 ÷ 3 = 6

So 11/3 + 2 1/3 = 6
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3 years ago
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Ierofanga [76]
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3 years ago
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g In American roulette, the wheel has the 38 numbers, 00, 0, 1, 2, ..., 34, 35, and 36, marked on equally spaced slots. If a pla
earnstyle [38]

Answer:

The expected value for the player to play one time is -$0.05.

Step-by-step explanation:

The expected value of a random variable <em>X</em> is given by the formula:

E(X)=\sum x\cdot P(X)

The American roulette wheel has the 38 numbers, {i = 00, 0, 1, 2, ..., 34, 35, and 36}, marked on equally spaced slots.

The probability that the ball stops on any of these 38 numbers is same, i.e.

P (X = i) = \frac{1}{38}.

It is provided that a a player bets $1 on a number.

If the player wins, the player keeps the dollar and receives an additional $35.

And if the player losses, the dollar is lost too.

So, the probability distribution is as follows:

<em>     X </em>: $35      -$1

P (<em>X</em>) :   \frac{1}{38}         \frac{37}{38}  

Compute the expected value of the game as follows:

E(X)=\sum x\cdot P(X)

         =[\$35\times \frac{1}{38}]+[-\$1\times \frac{37}{38}]\\\\=\frac{\$35-\$37}{38}\\\\=-\frac{\$2}{38}\\\\=-\frac{1}{19}\\\\=-0.052632\\\\\approx -\$0.05

Thus, the expected value for the player to play one time is -$0.05.

7 0
3 years ago
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