All categories

3 years ago

Someone pls help . Thank you sm !!

Mathematics

2 answers:

NemiM [27]3 years ago

6 0

Answer:

28 = -3k + 7

28 - 7 = -3k

21 = -3k

21/-3 = k

k = -7

1/5 x - 17 = 3

x/5 = 3 + 17

x/5 = 20

x = 5*20

x = 100

82 = 7/10 G + 12

82 - 12 = 7G/10

70 = 7G/10

70*10 = 7G

700 = 7G

700/7 = G

G = 100

N76 [4]3 years ago

4 0

The last 2 are 100 I’m not sure about the first one

You might be interested in

follow me friends and i will rate u 5 stars and i will given thanks also..... i will make u as brainlist

Nina [5.8K]

Answer:

Ok I will! Did it.

Step-by-step explanation:

3 0

3 years ago

(2+0.4 + 0.6)² I have been stuck on this problem for a while

Anna11 [10]

$\begin{gathered} \Rightarrow(2+0.4+0.6)^2 \\ \Rightarrow(2+1)^2 \\ \Rightarrow3^2 \\ \Rightarrow9 \end{gathered}$

7 0

1 year ago

Q = (√x-5)² + (√x+4)-41

kicyunya [14]

Answer:

. .

Step-by-step explanation:

x^2-9x√x-12

solve by using formula (a+b)^2 and open the brackets

6 0

3 years ago

Read 2 more answers

Select a number to make the following statement true. 0.07 is 10 times as great as

Mumz [18]

Answer:

the answer is 0.007 kkkkkk

4 0

3 years ago

Read 2 more answers

Find the sum of the equation

stealth61 [152]

Answer:

$\frac{{y}^{2}+13y-6}{{(y-1)}^{2}(y+7)}$

Step-by-step explanation:

1) Rewrite ${y}^{2}-2y+1y$ in the form ${a}^{2}-2ab+{b}^{2}$ , where a = y and b = 1.

$\frac{y}{{y}^{2}-2(y)(1)+{1}^{2}}+\frac{6}{{y}^{2}+6y-7}$

2) Use Square of Difference: ${(a-b)}^{2}={a}^{2}-2ab+{b}^{2}$ .

$\frac{y}{{(y-1)}^{2}}+\frac{6}{{y}^{2}+6y-7}$

3) Factor ${y}^{2}+6y-7$ .

1 - Ask: Which two numbers add up to 6 and multiply to -7?

-1 and 7

2 - Rewrite the expression using the above.

$(y-1)(y-7)$

Outcome/Result: $\frac{y}{(y-1)^2} +\frac{6}{(y-1)(y+7)}$

4) Rewrite the expression with a common denominator.

$\frac{y(y+7)+6(y-1)}{{(y-1)}^{2}(y+7)}$

5) Expand.

$\frac{{y}^{2}+7y+6y-6}{{(y-1)}^{2}(y+7)}$

6) Collect like terms.

$\frac{{y}^{2}+(7y+6y)-6}{{(y-1)}^{2}(y+7)}$

7) Simplify ${y}^{2}+(7y+6y)-6y$ to ${y}^{2}+13y-6y$

$\frac{{y}^{2}+13y-6}{{(y-1)}^{2}(y+7)}$

5 0

2 years ago

Read 2 more answers