Solve for x:x/5 - 2 = x/2 + 3
Put each term in x/5 - 2 over the common denominator 5: x/5 - 2 = x/5 - (10)/5:x/5 - (10)/5 = x/2 + 3
x/5 - (10)/5 = (x - 10)/5:(x - 10)/5 = x/2 + 3
Put each term in x/2 + 3 over the common denominator 2: x/2 + 3 = x/2 + 6/2:(x - 10)/5 = x/2 + 6/2
x/2 + 6/2 = (x + 6)/2:(x - 10)/5 = (x + 6)/2
Multiply both sides by 10:(10 (x - 10))/5 = (10 (x + 6))/2
10/5 = (5×2)/5 = 2:2 (x - 10) = (10 (x + 6))/2
10/2 = (2×5)/2 = 5:2 (x - 10) = 5 (x + 6)
Expand out terms of the left hand side:2 x - 20 = 5 (x + 6)
Expand out terms of the right hand side:2 x - 20 = 5 x + 30
Subtract 5 x from both sides:(2 x - 5 x) - 20 = (5 x - 5 x) + 30
2 x - 5 x = -3 x:-3 x - 20 = (5 x - 5 x) + 30
5 x - 5 x = 0:-3 x - 20 = 30
Add 20 to both sides:(20 - 20) - 3 x = 20 + 30
20 - 20 = 0:-3 x = 30 + 20
30 + 20 = 50:-3 x = 50
Divide both sides of -3 x = 50 by -3:(-3 x)/(-3) = 50/(-3)
(-3)/(-3) = 1:x = 50/(-3)
Multiply numerator and denominator of 50/(-3) by -1:Answer: x = (-50)/3
Answer:
Blue balloons = 12
Step-by-step explanation:
Total no of balloons = 21
Let us assume that the ratio of blue balloons to green balloons is 4:3.
Let there are 4x blue balloons and 3x green balloons.
ATQ,
4x+3x = 21
7x = 21
x = 3
Blue balloons = 4x
= 4(3)
= 12
Hence, she will have 12 blue balloons at her party.
Answer:
I, II, and IV
Step-by-step explanation:
(I) the probability of a Type I error.
(II) known as the alpha risk.
(IV) the sum of probabilities in the two tails of the normal distribution.
Answer:
B : y − 3 = 2/3 ⋅ ( x − 3 )
Step-by-step explanation:
Answer = 48.72
First find 16% of 42 which is just 16/100×42 which is 6.72 and then added 42
