Question

During the first 50 minutes of flight, the Concorde climbs from ground level to an altitude of about 52,000 ft. What is the concordes rate of change in altitude during this time? Round your answer to the nearest hundred

Answer 1

Let

x--------> the time in minutes

y-------> an altitude in feet

we know that

For x=0 min  y=0 ft

For x=50 min y=52,000 ft

so

the rate of change is equal to calculate the slope of the linear equation

$\frac{52,000-0}{50-0}=\frac{52,000}{50}=1,040\frac{ft}{min}$

Round to the nearest hundred-------->$1,000\frac{ft}{min}$

therefore

the answer is

$1,000\frac{ft}{min}$