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pashok25 [27]
3 years ago
15

Sara drives 171 miles on 7.6 gallons of gas. She uses this information to calculate how many miles per gallon she can drive. Usi

ng this result, how many miles can Sara drive on 12.5 gallons of gas?
Mathematics
2 answers:
vfiekz [6]3 years ago
7 0

171 / 7.6 = 22.5 miles per gallon

22.5 x 12.5 = 281.25 miles she can drive

IrinaK [193]3 years ago
5 0

Answer:

She can drive 281.25 miles in 12.5 gallons.

Step-by-step explanation:

Consider the provided information.

Sara drives 171 miles on 7.6 gallons of gas.

Thus in 1 gallons of gas she can drives:

171\ miles = 7.6\ gallons

\frac{171}{7.6}\ miles =1\ gallon

22.5\ miles =1\ gallon

She can travel 22.5 miles in one gallon or she can drive 22.5 miles per gallon.

To find how many miles she can drive on 12.5 gallons of gas, simply multiply the number 22.5 with 12.5.

22.5×12.5=281.25

Hence, she can drive 281.25 miles in 12.5 gallons.

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N76 [4]

Answer:

x : y = 9 : 13

Step-by-step explanation:

Given that

3x - y : x + 2y = 2 : 5

Express the ratio in fractional form, that is

\frac{3x-y}{x+2y} = \frac{2}{5} ( cross- multiply )

5(3x - y) = 2(x + 2y) ← distribute parenthesis on both sides )

15x - 5y = 2x + 4y ( subtract 2x from both sides )

13x - 5y = 4y ( add 5y to both sides )

13x = 9y ( divide both sides by 13 )

x = \frac{9}{13} y ( divide both sides by y )

\frac{x}{y} = \frac{9}{13} , that is

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4 years ago
Mr. Ramirez built a wooden storage shed for his tools. The dimensions of the shed are shown below. What is the volume of the sto
ankoles [38]

Answer:

Volume = 24\ ft^3

Step-by-step explanation:

Given [Missing from the question]

Length = 170cm\\ Width = 100cm\\ Height = 40cm

Required

Determine the volume

This is calculated as:

Volume = Length * Width * Height

Volume = 170cm * 100cm * 40cm

Volume = 680000cm^3

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3 years ago
HELP ASAP PLZZZZ
Tcecarenko [31]
QUESTION 1

The given system of equations is

3d - e = 7...eqn(1)
d + e = 5...eqn(2)

To solve by linear combination, we add equation (1) to equation (2) to get,

3d  + d= 7 + 5


4d = 12


We divide through by 4 to obtain,


d =  \frac{12}{4}


d = 3


We put d=3 into equation (2) to get,



3+ e = 5


e = 5 - 3


e = 2


\boxed {The \: solution \: is  \: (3, 2)}



QUESTION 2


The given system is

4x + y = 5 ...eqn(1)

3x + y = 3 ...eqn(2)


To solve by linear combination, we subtract equation (2) from equation (1) to eliminate y from the equation.

This will give us,

4x - 3x = 5 - 3



This implies that,

x = 2


Put x=3 into equation (1) to get,

4(2) + y = 5

8+ y = 5


y = 5 - 8



y =  - 3

The solution is

(2,-3)



QUESTION 3

We want to solve the system;


a – 2b = –2 ....eqn(1)


2a + 2b = 14...eqn(2)

by linear combination.


We need to add equation (1) to equation (2) to eliminate b.


This implies that,

2a + a = 14 +  - 2




Simplify,

3a = 12



Divide both sides by 3 to get,


a = 4
Put a=4 into equation (2) to obtain,



2(4) + 2b = 14


8 + 2b = 14
2b = 14 - 8


2b = 6


b = 3


The ordered pair in the form (a, b) is

(4,3)



QUESTION 4

The given system of equations is


11x + 4y = 18 ...eqn(1)

3x + 4y = 2 ...eqn(2)


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11x - 3x = 18 - 2


8x = 16


x = 2


Put x=2 into equation (2) to obtain,


3(2) + 4y = 2


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6 + 4y = 2


4y = 2 - 6


4y =  - 4


y=-1

The correct answer is (2,-1).




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The given system is ;

2d + e = 8...eqn1

d – e = 4...eqn2


We add the two equations to eliminate e.


This implies that,

2d + d = 8 + 4


3d = 12



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d = 4


We put d=4 into equation (2) to get,

4 - e = 4

- e = 4 - 4



- e = 0



e = 0


The solution is

(4,0)
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