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4 years ago

13

Over the summer, for every 12 okra seeds Dana planted, 7 grew into plants. If he planted 156 okra seeds, how many grew into plan

ts?

1 answer:

marissa [1.9K]4 years ago

6 0

267.4... Make a proportion, which is what I did ---->
7 over 12 equals 156 over x. Cross multiply and divide. Find x, and there you go.

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Two cars leave Phoenix and travel along roads 90 degrees apart. If Car 1 leaves 30 minutes earlier than Car 2 and averages 42 mp

beks73 [17]

Answer:

C. 210 miles.

Step-by-step explanation:

If Car 1 left 30 minutes earlier

than Car 2 therefore Car 2 traveled 3 hours

compared to Car 1's 3.5 hours

Car 1 traveled 3.5 x 42 mph = 147 miles

Car 2 travelled 3 x 50 mph = 150 miles

The distance between them would be

√147^2 + 150^2

= 210

8 0

4 years ago

Ahhhhhh please help me!!

netineya [11]

Answer: chrome

Step-by-step explanation:

new tab then search it up

7 0

2 years ago

The next two numbers in the series, 32000, 8000, 2000, 500 are

Travka [436]

$32000 \div 4 = 8000$
$8000 \div 4 = 2000$
$2000 \div 4 = 500$
$500 \div 4 = 125$
$125 \div 4 = 31.25$

3 0

3 years ago

Read 2 more answers

Use Newton's method to approximate a root of the equation 3x^(7) + 2x^(4) + 2 = 0 as follows. Let x1 = 3 be the initial approxim

Maurinko [17]

Answer:

$x_{2}\approx 2.59, x_{4}\approx 4.3$

Step-by-step explanation:

1) Given that the formula for the Newton Method is:

$x_{n+1}=x_{n}-\frac{f(x_{n})}{f(x_{n+1})}$

2) The Function and its 1st derivative

$f(x)=3x^{7}+2x^{4}+2\\f'(x)=21x^{6}+8x^{3}$

3) Let's work with the first approximation. Plugging in in the function:

$f(x)=3x^{7}+2x^{4}+2\Rightarrow f(3)=3(3)^{7}+2(3)^{3}+2\Rightarrow f(3)=6617\\f'(x)=21x^{6}+8x^{3}\Rightarrow f'(3)=21(3)^{6}+8(3)^{4}\Rightarrow f'(3)=15957\\\\x_{n+1}=x_{n}-\frac{f(x_{n})}{f'(x_{n})}\Rightarrow x_{2}=x_{1}-\frac{f(x_{1})}{f'(x_{1})}\\x_{2}=3-\frac{6617}{15957}\Rightarrow x_{2}\approx 2.59\\\\$

4) To approximate the other root x

$f(x)=3x^{7}+2x^{4}+2\Rightarrow f(5)=3(5)^{7}+2(5)^{3}+2\Rightarrow f(5)=234627\\f'(x)=21x^{6}+8x^{3}\Rightarrow f'(5)=21(5)^{6}+8(5)^{4}\Rightarrow f'(5)=333125\\\\x_{n+1}=x_{n}-\frac{f(x_{n})}{f'(x_{n})}\Rightarrow x_{4}=x_{3}-\frac{f(x_{1})}{f'(x_{1})}\\x_{4}=5-\frac{234627}{333125}\Rightarrow x_{4}\approx 4.3$

5 0

3 years ago

.9 is 1/10 of .09 true or false

vodomira [7]

Answer:

False.

Step-by-step explanation:

.9 is not 1/10 of .09

.09 is 1/10 of .9

.9 is 10 times .09

5 0

3 years ago