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ycow [4]
2 years ago
10

A plastic alphabet cube is 7 cm on each side. What is the surface area of the cube?

Mathematics
2 answers:
Viktor [21]2 years ago
8 0

Answer:

<u>Cube's features</u>;

  • <em>6 sides to a cube</em>
  • <em>All side lengths are equal, so all areas are the same</em>

Given this information, we must find the area of one side and multiply that area by 6 since there are 6 equal sides of the same area.

Formula for area of square:-

A = a^2

or

A = a · a

Where 'a' represents the length of one side.

Plug in values;

A = a^2

A = 7^2

A = 49 centimetres is the area of one side.

Now we find the areas of all sides (6 sides in total);

49(6)

= <u>294</u> is the surface area of the cube.

MrRa [10]2 years ago
6 0

Answer:

In a cube, the length and width are the same, so both sides will be 7 cm, yielding an area of 49 square centimeters.

Step-by-step explanation:

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a charitable organization in Lanberry is hosting a black tie benefit. Yesterday, the organization sold 55 regular tickets and 49
jenyasd209 [6]

Answer:

  • regular: $67
  • VIP: $122

Step-by-step explanation:

Let r and v represent the costs of a regular and VIP ticket, respectively. The two sales can be represented by ...

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We can subtract 7 times the second equation from 12 times the first to eliminate the v terms.

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  660r +588v -553r -588v = 115,956 -108,787 . . . . . eliminate parentheses

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A regular ticket costs $67; a VIP ticket costs $122.

_____

<em>Additional comment</em>

When using "elimination" to solve a system of equations, you're looking for coefficients of the same variable that are related by small factors. Preferably, one coefficient is the same as, or a small multiple of, the other. Here, 55 and 79 (the coefficients of x) are not related by an integer, or a couple of small integers. On the other hand, the y-coefficients 49 and 84 have a common factor of 7, and are in the ratio 7:12, a pair of small numbers. This is why we chose to eliminate the y-variable.

The x-variable could be eliminated using 55 and -79 as multipliers of the equations. This results in larger numbers, and more chance for error. (Errors tend to creep in when computing or copying large numbers.)

Of course, any of several machine methods could be used to solve these equations, including graphing and matrix-solving functions. Here, we tried to honor the requirement to solve by elimination.

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Answer:

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