Answer:
the answer is partick the star 244
Step-by-step explanation:
Dude where is the Whole question like???
Answer:
Height of the antenna = 28 ft (Approx)
Given:
Length of base = 300 ft
Angle of elevation to the building = 40°
Angle of elevation to the antenna = 43°
Find:
Height of the antenna
Computation:
Using trigonometry function:
Tan40° = Height of building / Length of base
Height of building = 251.73 ft
Tan43° = [Height of building + Height of the antenna] / Length of base
0.9325 = [251.73 + Height of the antenna] / 300
Height of the antenna = 28.02 ft
Height of the antenna = 28 ft (Approx)
Hello @14mullinsalf,
How are you doing? So, automatically,
we put the fraction
After that, you may want to simplify the answer.
Find the GCD (or HCF) of numerator and denominatorGCD of 48 and 60<span> is </span><span>12
</span>
<span>
Divide both the numerator and denominator by the GCD</span>
Your answer is 
I hope I helped, and contact me if you need further assistance.
Thank you,
Darian D.
Answer:
A
5(15x-4)^3
Explanation:
I assume you mean g(f(h(x))) so in that case here is how you do it:
So the first one is g(x) which is:
5x^3
Now g(f(x)) you just plug in f(x) for the x in the g equation. It would look like this:
5(5x-4)^3
Now the h(x) you would do the same, plug it in for all the values of x in g(x). So it would look like this:
5(5(3x)-4)^3
Since you simplify, you get 5(15x-4)^3
This final equation is g(f(h(x))) which is what you were looking for, which is A