What is the area of a parallelogram whose vertices are A(−12, 2) , B(6, 2) , C(−2, −3) , and D(−20, −3) ? Enter your answer in t

Question

bija089 [108]

4 years ago

15

What is the area of a parallelogram whose vertices are A(−12, 2) , B(6, 2) , C(−2, −3) , and D(−20, −3) ? Enter your answer in t

he box.

Mathematics

1 answer:

agasfer [191] · Answer 1 · 2022-01-06T00:48:30+03:00

agasfer [191]4 years ago

4 0

Answer:

$\boxed{90}\,\text{units$^2$}$

Step-by-step explanation:

The sides AB and CD are parallel to the x-axis and 5 units apart. The length of side AB is 6-(-12) = 18 units. The area is the product of these dimensions:

Area = (Base)(Height) = (18 units)(5 units) = 90 units²