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GREYUIT [131]
3 years ago
9

Find the slope-intercept form of the equation of the line through the point (0, -4) and (1, 0).

Mathematics
1 answer:
Arisa [49]3 years ago
4 0

Answer:

The Slope Intercept form of the equation through the point (0, -4) and

(1, 0)  is  y = 4 x - 1

Step-by-step explanation:

Here, the given points are A (0,-4) and B(1,0)

Now, slope of the equation with points (a,b) and (c,d) is given as

m = \frac{d - b}{c -a}

So, here the slope of the line AB is given as:

m = \frac{0 - (-4)}{1-0} = \frac{4}{1}  = 4

⇒ m = 4

Now, by POINT SLOPE  form:

The equation with slope m and point  (x0 , y0) is represented as :

(y-y0)  = m (x-x0)

⇒ The equation of AB is of the form with point (1,0) is

y - 0 = 4 (x -1)

or, y = 4 x - 1

Also, the SLOPE INTERCEPT form of an equation is of the form

y = m x + C ;     m = slope and C =  y -intercept

Hence, the slope intercept form of the equation through the point (0, -4) and (1, 0)  is  y = 4 x - 1

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A car travels 240 kilometers in 2 1/2 hours what is its speed
Oksanka [162]

Answer:

v = 96 km/h

Step-by-step explanation:

Data:

d = 240 km

t = 2.5 h

speed = d/t

speed = 240/2.5 = 96 km/h

8 0
3 years ago
Kenny bought a few 2-litre bottles of detergent. Sue bought a few 3-litre bottles of detergent. The average amount of detergent
exis [7]
They both bought 1 bottle each.

4 0
3 years ago
write the factored form for a quadratic equation with x-intercepts of -6 and -2 and the point (-3,-6) is on the parabola
kenny6666 [7]
F(x)=a(x-x1)(x-x2)
F(x)=a(x- - 6)(x- -2)
F(x)=a(x+6)(x+2)
-6=a(-3+6)(-3+2)
-6=a(3)(-1)
-6=-3a
2=a

Equation: f(x)=2(x+6)(x+2)
6 0
3 years ago
A cold tablet contains the following amounts of active ingredients: acetaminophen 325 mg, chlorpheniramine maleate 2 mg, and dex
kakasveta [241]

Answer:

The number of tablets that can be prepared is 3076.

Step-by-step explanation:

The total amount of active ingredients in the tablet is the sum of the amounts provided in the formula:

325 mg + 2mg+15 mg=342 mg

The percentages of each component in the formula are:

Acetaminophen:\frac{325mg*100}{342mg}=95.03%

Chlorpheniramine maleate:\frac{2mg*100}{342mg} =0.58%

Dextromethorphan hydrobromide:\frac{15mg*100}{342mg}=4.39%

If 1 Kg=10^{6} mg of acetaminophen is used, the needed amount of chlorpheniramine maleate would be:

\frac{10^{6} mg *0.58}{95.03}=6153.85 mg

Since there are 125 g = 125000 mg of chlorpheniramine maleate, there is enough of these ingredient to run the available acetaminophen out. Thus, the total amount of active ingredients that can be prepared with 1 kg of acetaminophen is:

\frac{10^{6}mg*100}{95.03}=1052307.7mg

Since each tablet weighs 342 mg, the number of tablets that can be prepared is:

\frac{1052307.7mg}{342mg}=3076.923

Which means that 3076 tablets can be prepared and a there will be a remanent of 0.923*342 mg = 315.69 mg of active ingredients.

7 0
3 years ago
Hello can someone please help me (with explanation ) how to do this <br><br> thank you.............
tigry1 [53]

Answer:

A 24 because half of 12 is 6 then 6 x 4 is 24

B 90÷3 is 30 which is 2/3 of 45

Hope this helps you

6 0
3 years ago
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