Answer:
The volume of the toy is 
Step-by-step explanation:
step 1
Find the volume of the hemisphere
The volume of the hemisphere is given by the formula
In this problem, the wide of the toy is equal to the diameter of the hemisphere
so
----> the radius is half the diameter
substitute
step 2
Find the volume of the cone
The volume of the cone is given by
we know that
The radius of the cone is the same that the radius of the hemisphere
so
The height of the cone is equal to subtract the radius of the hemisphere from the height of the toy
substitute the given values
step 3
Find the volume of the toy
we know that
The volume of the toy, is equal to the volume of the cone plus the volume of the hemisphere.
so
assume
Hey!
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They already give us the slope, so we can solve the y-intercept.
We can use (3, -2).
y = 8x + b
-2 = 8(3) + b
-2 = 24 + b
-2 - 24 = 24 + b - 24
-26 = b
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Hence, the answer is 
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Hope This Helped! Good Luck!
Answer:
Step-by-step explanation:
![f(x)=4\sqrt{2x^3-1}=4\left(2x^3-1\right)^\frac{1}{2}\\\\f'(x)=4\cdot\dfrac{1}{2}(2x^3-1)^{-\frac{1}{2}}\cdot3\cdot2x^2=\dfrac{12x^2}{(2x^3-1)^\frac{1}{2}}=\dfrac{12x^2}{\sqrt{2x^3-1}}\\\\\text{used}\\\\\sqrt{a}=a^\frac{1}{2}\\\\\bigg[f\left(g(x)\right)\bigg]'=f'(g(x))\cdot g'(x)\\\\\bigg[nf(x)\bigg]'=nf'(x)\\\\(x^n)'=nx^{n-1}](https://tex.z-dn.net/?f=f%28x%29%3D4%5Csqrt%7B2x%5E3-1%7D%3D4%5Cleft%282x%5E3-1%5Cright%29%5E%5Cfrac%7B1%7D%7B2%7D%5C%5C%5C%5Cf%27%28x%29%3D4%5Ccdot%5Cdfrac%7B1%7D%7B2%7D%282x%5E3-1%29%5E%7B-%5Cfrac%7B1%7D%7B2%7D%7D%5Ccdot3%5Ccdot2x%5E2%3D%5Cdfrac%7B12x%5E2%7D%7B%282x%5E3-1%29%5E%5Cfrac%7B1%7D%7B2%7D%7D%3D%5Cdfrac%7B12x%5E2%7D%7B%5Csqrt%7B2x%5E3-1%7D%7D%5C%5C%5C%5C%5Ctext%7Bused%7D%5C%5C%5C%5C%5Csqrt%7Ba%7D%3Da%5E%5Cfrac%7B1%7D%7B2%7D%5C%5C%5C%5C%5Cbigg%5Bf%5Cleft%28g%28x%29%5Cright%29%5Cbigg%5D%27%3Df%27%28g%28x%29%29%5Ccdot%20g%27%28x%29%5C%5C%5C%5C%5Cbigg%5Bnf%28x%29%5Cbigg%5D%27%3Dnf%27%28x%29%5C%5C%5C%5C%28x%5En%29%27%3Dnx%5E%7Bn-1%7D)
Rectangular and polar forms are two forms of equations that translates to plot. In this case, the two forms are convertible to each other by the expressions:
r sin theta = y
r cos theta = x
x2 + y2 = r2
we are given the polar expression r csc theta = 8 and is asked to convert to rectangular form.
in this case, csc theta is equal to 1/ sin theta. thys
r / sin theta = 8
in order to make use of the equations above, then
we multiply r to both numerator and denominator in the left side, that is
r^2 / r sin theta = 8
x2+y2 / y = 8
x 2 + y2 = 8y
It doesn’t s 19% I hope this helps bye
