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4 years ago

Two lines, C and D, are represented by the equations given below:

1 answer:

4 0

Given:
line C: y = x + 14
line D: y = 3x + 2

(6,20) or (3,11)

line C: y = 6 + 14 = 20 or y = 3 + 14 = 17
line D: y = 3(6) + 2 = 18 + 2 = 20 or y = 3(3) + 2 = 9 + 2 = 11

(6,20), because both lines pass through this point.

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Step-by-step explanation:

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3 years ago

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How do you factor this trinomial 4a^2-4a+1

ElenaW [278]

Answer:

$(2a-1)(2a-1)$

Step-by-step explanation:

To write the factored form, multiply a*c from the standard form $ax^2+bx+c$ . Here it is 4*1 = 4.

Then find factors of 4 that add to b=-4.

4: 1,2,4

-2+-2 = -4

Split the middle term into -2x+-2x and factor by grouping.

$4a^2-2a+-2a+1\\(4a^2-2a)+(-2a+1)\\2a(2a-1)-1(2a-1)\\(2a-1)(2a-1)$

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3 years ago

The sum of the measures of the angles of a triangle is 180. The sum of the measures of the second and third angles is twice the

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2 years ago

Factor −5x2 + 10x. −5x(x + 2) 5(−x2 + 10x) 5x(−x + 2) x(5x + 10)

Hitman42 [59]

${ \red{ \bold{option \: (c)}}}$

Step-by-step explanation:

${ \purple{ \tt{ { - 5x}^{2} + 10x}}}$

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${ \purple{ \tt{5x( - x + 2)}}}$

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1 year ago

1. Write an equation in slope-intercept form for a line passing through (-3,3) with a slope of 1.

PIT_PIT [208]

$\bf (\stackrel{x_1}{-3}~,~\stackrel{y_1}{3})~\hspace{10em} slope = m\implies 1 \\\\\\ \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-3=1[x-(-3)] \\\\\\ y-3=1(x+3)\implies y-3=x+3\implies y=x+6$

$\bf (\stackrel{x_1}{-4}~,~\stackrel{y_1}{2})\qquad (\stackrel{x_2}{1}~,~\stackrel{y_2}{12}) \\\\\\ slope = m\implies \cfrac{\stackrel{rise}{ y_2- y_1}}{\stackrel{run}{ x_2- x_1}}\implies \cfrac{12-2}{1-(-4)}\implies \cfrac{10}{1+4}\implies \cfrac{10}{5}\implies 2 \\\\\\ \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-2=2[x-(-4)]\implies y-2=2(x+4) \\\\\\ y-2=2x+8\implies y=2x+10$

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4 years ago