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kenny6666 [7]
4 years ago
7

Two lines, C and D, are represented by the equations given below:

Mathematics
1 answer:
hammer [34]4 years ago
4 0
Given:
line C: y = x + 14
line D: y = 3x + 2

(6,20) or (3,11)

line C: y = 6 + 14 = 20  or y = 3 + 14 = 17
line D: y = 3(6) + 2 = 18 + 2 = 20   or  y = 3(3) + 2 = 9 + 2 = 11

(6,20), because both lines pass through this point.
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How do you do simplfi 32/100
poizon [28]

The reduced form of  

\frac{32}{100}  = \frac{8}{25}

3 0
3 years ago
What is 87.252 dividend by 2.2 I am not sure how to do the work
WARRIOR [948]

Answer:

39.66

Step-by-step explanation:

If the divisor is not a whole number, move decimal point to right to make it a whole number and move decimal point in dividend the same number of places.

Divide like you usually do

Put decimal point directly above decimal point in the dividend.

Check your answer.


7 0
3 years ago
Read 2 more answers
Solve the following system of equations using the elimination method. 4x + 2y = 12 4x + 8y = –24
Hunter-Best [27]

Answer:

my answer for y is -6, x is -10

Step-by-step explanation:

just eliminate the -4s by subtracting them and you will get the value of y.

now you can use either eqn (I) or (ii) which are first and second.

anyone you decide to choose just replace y by the value you got and you will get the value of x.

pls try to do it buddy you can

4 0
2 years ago
Please help me with this quick :))))))))
vredina [299]

Answer:

129.3 in²

Step-by-step explanation:

The shaded segment is calculated as

area of sector ABC - area of triangle ABC

area of sector = area of circle × fraction of circle

A = πr² × \frac{60}{360}

   = π × 18² × \frac{1}{6}

   = 324π × \frac{1}{6} = 54π in²

area of Δ ABC = \frac{1}{2} × 18 × 18 × sin60°  ≈ 40.30 in²

Then

shaded area = 54π - 40.30 ≈ 129.3 in² ( to the nearest tenth )

6 0
3 years ago
In constructing a box-and-whisker plot for the data set below, at which values would you draw the left and right sides of the bo
finlep [7]
Lets put these numbers in order
1,2,3,3,4,5,6,7,8,8,9

Q1 = 3
Q2 (median) = 5
Q3 = 8

the box starts at Q1 and ends at Q3....so left side is 3 and right side is 8
u r correct...it is A


7 0
3 years ago
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