The first thing to take into account is that the probability of getting any of the six numbers of the dice after rolling it is the same and that probability is 1/6. Here we are being asked about the probability of getting a 1 or a 4 or a 5. In order to find it we need to define which are our favourable cases. Favourable cases are the results we want to get when we roll the dice so getting a 1, a 4 or a 5 are all favourable cases. All the other possible outcomes are unfovourable cases: getting a 2, a 3 or a 6. So we have 3 favourable and 3 unfavourable cases. Adding them we know that the total amount of cases is 6. The probability we are looking for (i'm going to call it P) is given by these quantities I defined:

So the probability written as a simplified fraction is 1/2.
I think it’s 28,800 I’m not sure but I think if I’m wrong sorry
Answer and Step-by-step explanation:
1st box:
0, -3
2nd box
-2, -9/4
3rd box:
2, -3/2
4th box:
4, 0
Btw 0, -2, 2, 4 are in the x-coordinate column if you didn’t know, and 1, -9/4, -3/2 are in the y-coordinate column
Basically to solve if you plug in 0 into x, so basically it’s 3(0)-4y=12, which you simplify gives you 0-4y=12, subtract 0 from 12 which is 12 and then do 12 divided by -4 and then you get y = -3 and that’s how you get the box answer
Idk how to the rest srry lol!
Answer:
Hope this helps!!
Step-by-step explanation:
1200 x .25 = 300/ 1200 -300 = 900
900 x .25 = 225/ 900 - 225= 675
675 x .25 = 168.75/ 675 - 168.75= 431.25
431.25 x .25 = 107.8125/ 431.25 - 107.8125 = 323.4375
323.4375 x .25 = 80.859 / 323.4375 - 80.859 =242.758