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3 years ago

HELP! How many triangles can be made from the following three lengths: 1.6 centimeters, 7.4 centimeters, and 5.9 centimeters?

Mathematics

1 answer:

ziro4ka [17]3 years ago

4 0

Answer: one

Step-by-step explanation:

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Cosx.cosecx + sinx.secx

ElenaW [278]

Answer:

what does this mean

Step-by-step explanation:

huh I don't get it plz explain

8 0

3 years ago

If the volume of a cube is 729cm^3, what is the surfface area.<br><br> Thanks!!

bezimeni [28]

Answer:

486cm^2

Step-by-step explanation:

cube volume: 729cm^3

cube faces count: 6

How you calculate square area:

s(cm) * s(cm) or just s^2(cm^2)

s = side length

If you want to find out the side length of a cube by its volume. Then simply just remove the ^3 by taking the cubic root (also written ^(1/3))

729^(1/3) = 9

then just calculate the area like i showed earlier:

(9cm)^2 = 81cm^2

But that is only one side of a cube's 6 sides, so multiply by 6:

81cm^2 * 6 = 486cm^2

Hope i could help :D

Dont be scared to ask me questions..

4 0

3 years ago

An adjustable ladder on the back of the firetruck is needed for firefighters to climb to very high buildings. The maximum angle

torisob [31]

Cos 70 = horizontal distance /
100 horizontal distance = 100 cos 70 = 32.2feet

3 0

3 years ago

At an outpatient mental health clinic, appointment cancellations occur at a mean rate of 1.5 per day on a typical Wednesday. Let

Kamila [148]

Answer:

a) Cancellations are independent and similar to arrivals.

b) 22.31% probability that no cancellations will occur on a particular Wednesday

Step-by-step explanation:

In a Poisson distribution, the probability that X represents the number of successes of a random variable is given by the following formula:

$P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}$

In which

x is the number of sucesses

e = 2.71828 is the Euler number

$\mu$ is the mean in the given time interval.

Mean rate of 1.5 per day on a typical Wednesday.

This means that $\mu = 1.5$

(a) Justify the use of the Poisson model.

Each wednesday is independent of each other, and each wednesday has the same mean number of cancellations.

So the answer is:

Cancellations are independent and similar to arrivals.

(b) What is the probability that no cancellations will occur on a particular Wednesday

This is P(X = 0).

$P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}$

$P(X = 0) = \frac{e^{-1.5}*(1.5)^{0}}{(0)!} = 0.2231$

22.31% probability that no cancellations will occur on a particular Wednesday

5 0

3 years ago

Micaela tried to rotate the square 180 about the origin. Is her rotation correct? If not, explain why

Vinvika [58]

Answer:no the vertices of the image and pre image don’t correspond

Step-by-step explanation:

Just did it

7 0

3 years ago