Probably hundreds because I don’t think it’s that large
Answer:
The distance between the airplane and the airport is:
![c=6.64\: miles](https://tex.z-dn.net/?f=c%3D6.64%5C%3A%20miles)
Step-by-step explanation:
We can use the Pythagoras theorem to find the distance from the airplane to the airport.
The equation is:
![c^{2}=a^{2}+b^{2}](https://tex.z-dn.net/?f=c%5E%7B2%7D%3Da%5E%7B2%7D%2Bb%5E%7B2%7D)
Where:
- <u>a represents the elevations of the airplane (15000 feet)</u>
- <u>b is the distance from the ground directly below the airplane to the airport (6 miles)</u>
- <u>c is the distance between the airplane and the airport.</u>
We need first to convert 15000 feet in miles.
![15000\: feet \times \frac{0.00019\: miles}{1\: feet}=2.85\: miles](https://tex.z-dn.net/?f=15000%5C%3A%20feet%20%5Ctimes%20%5Cfrac%7B0.00019%5C%3A%20miles%7D%7B1%5C%3A%20feet%7D%3D2.85%5C%3A%20miles)
Therefore, c will be:
![c^{2}=a^{2}+b^{2}](https://tex.z-dn.net/?f=c%5E%7B2%7D%3Da%5E%7B2%7D%2Bb%5E%7B2%7D)
![c=\sqrt{a^{2}+b^{2}}](https://tex.z-dn.net/?f=c%3D%5Csqrt%7Ba%5E%7B2%7D%2Bb%5E%7B2%7D%7D)
![c=\sqrt{2.85^{2}+6^{2}}](https://tex.z-dn.net/?f=c%3D%5Csqrt%7B2.85%5E%7B2%7D%2B6%5E%7B2%7D%7D)
![c=6.64\: miles](https://tex.z-dn.net/?f=c%3D6.64%5C%3A%20miles)
I hope it helps you!
Hey there!
The answer is $48.44
We can solve this by first finding how much the discount is.
0.25 x 59.80
14.95
The amount of the discount is 14.95, so we then take the discount off.
59.80 - 14.95
44.85
Then, we find the amount of tax.
.08 x 44.85
3.588 (round to nearest cent = 3.59)
Then, add the price of the tax onto the price of the jeans.
3.59 + 44.85
48.44
Hope this helps! Good luck!
Answer:
I say B.
Step-by-step explanation:
sorry if I'm wrong. Have a nice day :)