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2 years ago

What is the unknown number that makes the equation true?

Mathematics

2 answers:

S_A_V [24]2 years ago

8 0

The answer is A 1,200

DerKrebs [107]2 years ago

5 0

Answer:

The answer is a. hope this helps :)

Step-by-step explanation:

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The Richter scale is used to measure the magnitude of an earthquake. The magnitude, R, is given by the earthquake. Determine the

8090 [49]

A) $R=0.65log(0.39E)+1.45

7.5=0.65log(0.39E)+1.45$

B) $6.05=0.65log(0.39E) Subtracted 1.45 from~ both~ sides~ of~ equation.

9.31=log(0.39E) Divided each side by 0.65. 

$

C) $9.31=log(0.39E)

10^(9.31)=0.39E

E=5.24*10^9 kilowatt hours$

5 0

3 years ago

My Notes The displacement from equilibrium of an oscillating weight suspended by a spring is given by y(t) = 1 4 cos(5t) where y

ikadub [295]

Answer:

y(0) = 0.25 feet

$y(\frac{1}{4}) = 0.0789 \text{ feet}$

$y(\frac{1}{2}) =-0.2003 \text{ feet}$

Step-by-step explanation:

We are given the following information in the question:

The displacement from equilibrium of an oscillating weight suspended by a spring =

$y(t) = \displaystyle\frac{1}{4} \cos(5t)$

where y is the displacement in feet and t is the time in seconds.

Here, cos is in radians.

1) t = 0

$y(0) = \displaystyle\frac{1}{4} \cos(5(0)) = \frac{1}{4} \cos(0) = \frac{1}{4}(1) = \frac{1}{4}$

y(0) = 0.25 feet

2) t = $\frac{1}{4}$

$y(\displaystyle\frac{1}{4}) = \displaystyle\frac{1}{4} \cos(5(\frac{1}{4})) = \frac{1}{4} \cos(1.25) = \frac{1}{4}(0.31532236) =0.07883059$

$y(\frac{1}{4}) = 0.0789 \text{ feet}$

3) t = $\frac{1}{2}$

$y(\displaystyle\frac{1}{2}) = \displaystyle\frac{1}{4} \cos(5(\frac{1}{2})) = \frac{1}{4} \cos(2.5) = \frac{1}{4}(-0.80114362) = -0.200285905$

$y(\frac{1}{2}) =-0.2003 \text{ feet}$

The negative sign indicates the opposite direction of displacement.

3 0

3 years ago

The picture is incorrect but what is the correct value of x

Monica [59]

Start with -3x + 2 = -7
Subtract 2 from each side
-3x = -9
Divide each side by -3
x = 3

6 0

3 years ago

If you roll two fair dice repeatedly, what is the probability that you will get a sum of 4 before you get a sum of 5 ? (a) (b) (

AlexFokin [52]

Answer:

The probability that you will get a sum of 4 before you get a sum of 5 is $\frac{1}{12}$

Step-by-step explanation:

Given : If you roll two fair dice repeatedly.

To find : What is the probability that you will get a sum of 4 before you get a sum of 5 ?

Solution :

When two dice are rolled the outcomes are

(1,1) (1,2) (1,3) (1,4) (1,5) (1,6)

(2,1) (2,2) (2,3) (2,4) (2,5) (2,6)

(3,1) (3,2) (3,3) (3,4) (3,5) (3,6)

(4,1) (4,2) (4,3) (4,4) (4,5) (4,6)

(5,1) (5,2) (5,3) (5,4) (5,5) (5,6)

(6,1) (6,2) (6,3) (6,4) (6,5) (6,6)

Total number of outcomes = 36

Favorable outcome get a sum of 4 before you get a sum of 5 is (1,3) ,(2,2) and (3,1) = 3

The probability that you will get a sum of 4 before you get a sum of 5 is

$P=\frac{3}{36}$

$P=\frac{1}{12}$

Therefore, The probability that you will get a sum of 4 before you get a sum of 5 is $\frac{1}{12}$

5 0

3 years ago

Write an expression that is equivalent to -0.5(20f – 16).

pashok25 [27]

Answer:

- 10f + 8

Step-by-step explanation:

Given expression:

- 0.5(20f - 16)

Distribute and simplify:

-0.5(20f) - 0.5(- 16) =
- 10f + 8

6 0

2 years ago

Read 2 more answers