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Gekata [30.6K]
3 years ago
5

HELP HELP HELP PLS PLS PLS

Mathematics
1 answer:
Sergio [31]3 years ago
4 0

Answer:

In order of the paragraph:

3, isosceles, greater, 3 in

Step-by-step explanation:

The first drop box has to be 3 because if you add up two sides of a triangle, the sum has to be greater than the third side. If two sides are equal, the triangle is isosceles. The third side cannot be 1 since 1+1 is not greater than 3. So the third side must measure 3in.

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Hello there
Amanda [17]

Answer:

210cm cubed

Step-by-step explanation:

Width x length x height

3x7x10

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Which is the best estimate for the mass of a pair of eyeglasses? A. 25 grams B. 250 grams C. 25 kilograms D. 250 kilograms
Yuliya22 [10]
About A. 25 grams because glasses are really not heavy at all and the other options are way too illogical.
Hope this helps!
4 0
3 years ago
Waiting Line Models:Movies tonight is a typical video and dvd movie rental outlet for home-viewing customers. During the weeknig
pentagon [3]

Answer:

  1. Probability [No customers in system] = 0.375
  2. Customers waiting for service = 25/24
  3. Average time customer wait = 1.25/1.5
  4. May be wait
  5. Per customer average time = 1.33 (Approx)

Step-by-step explanation:

Given:

Arrival rate λ = 1.25 min

Mean μ = 2

Computation:

(a) Probability [No customers in system]

Probability [No customers in system] = 1-[λ/μ]

Probability [No customers in system] = 1-[1.25/2]

Probability [No customers in system] = 0.375

(b) Customers waiting for service

Customers waiting for service = λ²/ [μ(μ-λ)]

Customers waiting for service = 1.25²/ [2(2-1.25)]

Customers waiting for service = 25/24

(c) Average time customer wait

Average time customer wait = λ / [μ(μ-λ)]

Average time customer wait = 1.25/ [2(2-1.25)]

Average time customer wait = 1.25/1.5

(d) May be wait because Customers waiting for service = 25/24

(e) Per customer average time

Per customer average time = 1/(μ-λ)

Per customer average time = 1/(2-1.25)

Per customer average time = 1.33 (Approx)

7 0
3 years ago
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