First one:
You take 10 + 3 =13 then add 9 then 5. That all equals 27. Then you add 1 for the top part that isn’t labeled because it’s 10 in the bottom then 9 at the top which means it’s 1. Then for the side that’s unlabeled it’s 2 since it’s all 5 then the other side is 3. Answer is 31
Second one:
This one is the same as #1. You add 14+6+3+4 = 27. The long horizontal unlabeled side is 11 bc 14-3 = 11. Then the other side 2. Answer is 30.
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Answer:
"complete the square" to put in vertex form
Step-by-step explanation:
It may be helpful to consider the square of a binomial:
(x +a)² = x² +2ax +a²
The expression x² +x +1 is in the standard form of the expression on the right above. Comparing the coefficients of x, we see ...
2a = 1
a = 1/2
That means we can write ...
(x +1/2)² = x² +x +1/4
But we need x² +x +1, so we need to add 3/4 to the binomial square in order to make the expressions equal:
_____
Another way to consider this is ...
x² +bx +c
= x² +2(b/2)x +(b/2)² +c -(b/2)² . . . . . . rewrite bx, add and subtract (b/2)²*
= (x +b/2)² +(c -(b/2)²)
for b=1, c=1, this becomes ...
x² +x +1 = (x +1/2)² +(1 -(1/2)²)
= (x +1/2)² +3/4
_____
* This process, "rewrite bx, add and subtract (b/2)²," is called "completing the square"—especially when written as (x-h)² +k, a parabola with vertex (h, k).
Answer: y - 5 = 0(x - 1)
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Explanation:
Recall that point slope form in general is written as such
y - y1 = m(x - x1)
where,
m is the slope
(x1,y1) is the point the line goes through
The given equation y = 7 can be written as y = 0x+7. So we see that this line has a slope of m = 0
Plug m = 0 along with the given point (x1,y1) = (1,5) into the point slope equation and we get
y - y1 = m(x - x1)
y - 5 = 0(x - 1)
which is the final answer
note: the equation in bold can be rearranged and simplified to get y = 5; however your teacher seems to want the answer in point-slope form, so we leave it as such.
Slope for (x₁, y₁) and (x₂, y₂): (6, 2) and (7, 4)
Slope: (y₂ -y₁) / (x₂ -x₁)
Slope: ( 4 - 2) / (7 - 6) = 2/1
<span>Slope = 2/1 = 2
Option D</span>
