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Sidana [21]
3 years ago
11

How do I work this out

Mathematics
1 answer:
gregori [183]3 years ago
4 0
P = a + b + c where a < b < c

P = 42 in
b = 18 in
a = x
c = 4x - 1

The equation:

x + 18 + 4x - 1 = 42    |combine items

5x + 17 = 42      |subtract 17 from both sides

5x = 25    |divide both sides by 5

x = 5 (in)

c = 4 · 5 - 1 = 20 - 1 = 19 (in)

Answer: The length of the longest side is 19 in.
You might be interested in
3/2 x - 5/4 y =15 rate of change​
Alenkinab [10]

Answer:

6/5

Step-by-step explanation:

m is your rate of change you need to get y by itself.

3/2x - 15 = 5/4y

3x/2 - 30/2 = 5/4y

3x-30/2 = 5/4y

3x - 30 = 2 x 5/4y

3x - 30 = 2 x 5/4x2y (cross out 2 and 4)

3x - 30 = 5/2y

2 x 3x - 2 x 30 = 2 x 5/4y

6x - 60 = 5y

6x/5 - 60/5 = 5y/5

y = 6/5 x x - 12

3 0
3 years ago
Please respond quickly
storchak [24]
A should be the right answer. Hope this helped!
6 0
3 years ago
Read 2 more answers
I Need The Answer Plz Geometry Is Hard!!
otez555 [7]

Answer:

14

Step-by-step explanation:

In a triangle, the midline joining the midpoints of two sides is parallel to the third side and half as long, so

FB = EC/2

2x - 6 = 44/2

2x - 6 = 22

2x = 22 + 6

2x = 28

x = 28/2

x = 14

6 0
3 years ago
Please help on this one!! I need it in ASAP :(
lisov135 [29]

Answer:

Hey there! here's your answer

Step-by-step explanation:

Speed = distance/Time

Speed = 3/5 ÷ 1/2

Speed = 3/5 * 2

Speed = 6/5 mph or 1.2 mph.

5 0
3 years ago
Read 2 more answers
Find the minimum and maximum value of the function on the given interval by comparing values at the critical points and endpoint
Kitty [74]

Answer:

maximum: y = 1

minimum: y = 0.

Step-by-step explanation:

Here we have the function:

y = f(x) =  √(1 + x^2 - 2x)

we want to find the minimum and maximum in the segment [0, 1]

First, we evaluate in the endpoints, which are 0 and 1.

f(0)  =√(1 + 0^2 - 2*0) = 1

f(1) = √(1 + 1^2 - 2*1) = 0

Now let's look at the critical points (the zeros of the first derivate)

To derivate our function, we can use the chain rule:

f(x) = h(g(x))

then

f'(x) = h'(g(x))*g(x)

Here we can define:

h(x) = √x

g(x) = 1 + x^2 - 2x

Then:

f(x) = h(g(x))

f'(x)  =  1/2*( 1 + x^2 - 2x)*(2x - 2)

f'(x) = (1 + x^2 - 2x)*(x - 1)

f'(x) = x^3 - 3x^2 + x - 1

this function does not have any zero in the segment [0, 1] (you can look it in the image below)

Thus, the function does not have critical points in the segment.

Then the maximum and minimum are given by the endpoints.

The maximum is 1 (when x = 0)

the minimum is 0 (when x = 1)

7 0
3 years ago
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