Borrow money from a relative, use credit cards to build up good credit, do a fundraiser. This is what you could do to pay off debts
Answer:
2:5
Step-by-step explanation:
Total marbles: 10
red: 2
yellow: 5
2:5
Answer:
The required specific heat is 196.94 joule per kg per °C
Step-by-step explanation:
Given as :
The heat generated = Q = 85.87 J
Mass of substance (m)= 34.8 gram = 0.0348 kg
Change in temperature = T2 - T1 = 34.29°C - 21.76°C = 12.53°C
Let the specific heat = S
Now we know that
Heat = Mass × specific heat × change in temperature
Or, Q = msΔt
Or, 85.87 = (0.0348 kg ) × S × 12.53°C
Or , 85.87 = 0.4360 × S
Or, S = 
∴ S = 196.94 joule per kg per °C
Hence the required specific heat is 196.94 joule per kg per °C Answer
Answer:
y = (1/2) cos (x)
Step-by-step explanation:
It has the same period as cos x but only goes half as high and half as low. Normalyy, cos(x) goes up to 1 and down to -1.
Answer:
pq are being multiplied together.the answer is D. pq. Hope it helps