Question

Find the dimensions of a rectangle whose area is 221 cm2 and whose perimeter is 60 cm. (enter your answers as a comma-separated list.)

Answer 1

60 = 2 ( length + width ) 

30 = length + width 

Let length be = x and width = y 

x+y = 30 

xy = 209 

4xy = 836 

( x+ y)^2 = 900 

( x+y)^2 - 4xy = 900-836 = 64 

( x-y)^2 = 64 

x- y = 8 

x+y = 30 

ADD 2x =38 

x = 19 

y = 11 

ANSWER 19cm X 11cm