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Ghella [55]
3 years ago
8

Alexa wrote down a decimal number that is greater than 2.4 but less than 2.8. Select two numbers that Alexa could have written d

own. * 1 point 2.50 2.41 2.39 2.40 2.08
Mathematics
1 answer:
Setler79 [48]3 years ago
3 0

Answer:

2.41 and 2.50

Step-by-step explanation:

Here, we shall be selecting the correct answer from the option.

a. A is correct

the number we want is between 2.4 and 2.8

2.5 is greater than 2.4 but less than 2.5, this means it meets our criteria

b. 2.41 is also correct

This is because it is greater than 2.4 but less then 2.8

c. wrong

2.4 is same as 2.4, it does not meet the criterion

d. wrong

the value is far lesser than 2.4

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Solve the system by substitution.<br> y = -4x<br> 23 - 5y = 44
spin [16.1K]
<h3><u>Explanation</u></h3>
  • Given the system of equations.

\begin{cases} y =  - 4x \\ 23 - 5y = 44 \end{cases}

  • Substitute y = -4x in the second equation.

23 - 5( - 4x) = 44 \\ 23 + 20x = 44 \\ 20x = 44 - 23 \\ 20x = 21 \\ x =  \frac{21}{20}

  • Substitute the value of x in any given equations. I will substitute the value of x in the first equation.

y =  - 4x \Longrightarrow y =  - 4( \frac{21}{20} ) \\ y =   \cancel{ - 4}( \frac{21}{ \cancel{20}} ) \Longrightarrow y =  -  \frac{21}{5}  \\ y =  -  \frac{21}{5}

  • Answer Check by substituting both values in two equations.

<u>First</u><u> </u><u>Equation</u>

y =  - 4x \Longrightarrow  -  \frac{21}{5}  =  - 4( \frac{21}{20} ) \\  -  \frac{21}{5}  =   \cancel{ - 4}( \frac{21}{ \cancel{20}} ) \\  -  \frac{21}{5}  =  -  \frac{21}{5}  \:  \:   \: \checkmark

<u>Second</u><u> </u><u>Equation</u>

23 - 5y = 44 \\ 23 - 5( -  \frac{21}{5} ) = 44 \\23 -  \cancel{5}( -  \frac{21}{ \cancel{5}} ) = 44 \\ 23 + 21 = 44 \\ 44 = 44 \:  \:  \:  \:  \checkmark

Both equations are true for the value of x and value of y.

<h3><u>Answer</u></h3>

<u>\begin{cases} x =  \frac{21}{20}  \\ y =  -  \frac{21}{5}  \end{cases}</u>

<u>Coordinate</u><u> </u><u>Point</u><u> </u><u>form</u>

<u>( \frac{21}{20} , -  \frac{21}{5} )</u>

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