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3 years ago

Need help solving for X

Mathematics

1 answer:

MakcuM [25]3 years ago

6 0

10 / 10+x = 35 / 56
560 = 350 + 35x
35x = 560 - 350
35x = 210
x = 210/35
x = 6

So, your final answer is 6

Hope this helps!

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Fish are swimming in groups of 10 there are 200 fish. How many groups are there

Naily [24]

200/10
=20
The answer is 20

5 0

4 years ago

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A radio station requires DJs to play 3 commercials for every 18 songs they play. What is the unit rate of songs to commercials?

bulgar [2K]

6 songs

The way to find this answer is to divide 18 by 3, which is six, which means that after every six songs a commercial is played.

Hope this was helpful and that I explained it correctly.

3 0

3 years ago

The equation C = 20n + 35 represents the relationship between the cost of school volleyball uniforms, C, in dollars, and the num

Margaret [11]

The equation represent a linear relation with the y-intercept

representing the amount of initial fee.

Correct response:

1. 28 volleyball uniforms

2. Price per uniform

3. Initial flat order fee

4. 10 fewer volleyball uniform

<h3>Methods used for finding the above values</h3>

The given equation that represents the relationship between the cost of school volleyball uniform is; C = 20·n + 35

Where;

C = The uniform costs

n = The number of volleyball uniform ordered

The maximum amount the school has to spend = $600

1. The number of uniforms the school can buy is given by setting C = 600 as follows;

C = 20·n + 35

Therefore;

600 = 20·n + 35

20·n = 600 - 35 = 565

$n = \dfrac{565}{20} = \mathbf{28.25}$

Rounding down to the nearest whole number, we have;

The number of uniforms the school can buy, n = 28 volleyball uniforms.

2. The number 20 represent the additional cost for each extra uniform, which is the unit cost therefore;

20 represents a $20 price per uniform.

3. The 35 in the equation represents an initial flat fee, such as an

ordering or initial fee, which is fixed.

Therefore;

The number 35 represent the fixed cost for producing the uniforms

4. The price per uniform of $30 changes the coefficient of n from 20 to 30 as follows;

C = 30·n + 35

The number of uniforms the school can by with $600 is therefore;

$n = \dfrac{600 - 35}{30} = \mathbf{18.8 \overline 3}$

Which gives;

The number of uniforms the school can purchase at $30 per uniform is n = 18 volleyball uniforms

The difference in the number of uniforms purchased = 28 - 18 = 10

Therefore;

The school can purchase 10 fewer uniforms at $30 per uniform

Learn more about linear equations here:

brainly.com/question/10452752

4 0

2 years ago

Simplify the number into simplest radical form. Use the factor tree to help determine the factors. StartRoot 96 Endroot StartRoo

adell [148]

Answer:

$[tex]4608\sqrt{3}$ [/tex]

Step-by-step explanation:

1. $\sqrt{96} *\sqrt{6}* 2*\sqrt{6}*4 *\sqrt{6} *4*\sqrt{3}$

2. $\sqrt{2^{5} *3} \sqrt{6} *2\sqrt{6}*4\sqrt{6}*4\sqrt{3}$ factoring 96

since $\sqrt{2^{5}*3 } = \sqrt{2^{5} } \sqrt{3}$

3. $\sqrt{2^{5} } \sqrt{3}\sqrt{6} *2\sqrt{6}*4\sqrt{6}*4\sqrt{3}$

using exponent rule - $(a^{b}) ^{c} = a^{bc}$

$\sqrt{2^{5} } = 2^{5/2}$

4. $2^{5/2}\sqrt{3}\sqrt{2*3} *2\sqrt{6}*4\sqrt{6}*4\sqrt{3}$

doing some simple simplification and $4=2^{2}$ and 6=2*3

5. $2^{5/2} \sqrt{3} \sqrt{2} \sqrt{3} *2\sqrt{2} \sqrt{3} *2^{2}\sqrt{2} \sqrt{3}*4\sqrt{3}$

collecting the roots on one side and applying exponent rule

6. $\sqrt{3} \sqrt{3}\sqrt{3} \sqrt{3}\sqrt{2} \sqrt{2}\sqrt{2} *2^{5/2+1+2+2} \sqrt{3}$

Applying exponents rule on all $\sqrt{3}$ and $\sqrt{2}$

7. $2^{1/2+1/2+1/2} *2^{5/2+1+2+2}*3^{1/2+1/2+1/2+1/2+1/2}$

combining all powers of 2

8. $2^{1/2+1/2+1/2+5/2+1+2+2}*3^{1/2+1/2+1/2+1/2+1/2}$

Simplifying

9. $2^{9} *3^{2}\sqrt{3}$

10. $512*9\sqrt{3}$

11. $4608\sqrt{3}$

8 0

3 years ago

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From a rope 11m long two pieces of lengths 13/5m and 33/10m are cut off. What is the length the remaining rope?

Serhud [2]

Answer:

$\frac{51}{10}$ m

Step-by-step explanation:

Given parameters:

Length of rope = 11m

First length cut off = $\frac{13}{5}$ m

Second length cut off = $\frac{33}{10}$ m

Unknown:

Remaining length = ?

Solution:

Let us find the total length cut off first;

= $\frac{13}{5}$ m + $\frac{33}{10}$ m

= $\frac{26 + 33}{10}$

= $\frac{59}{10}$ m

So,

Remaining length = 11 - $\frac{59}{10}$

= $\frac{110 - 59}{10}$

= $\frac{51}{10}$ m

5 0

3 years ago