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katovenus [111]

3 years ago

13

Find the leg (in inches) of the triangle whose hypotenuse is 10 inches and whose other leg is 3.25 inches. Round to the nearest

tenth. JUST ENTER THE NUMBER

1 answer:

alekssr [168]3 years ago

7 0

Answer:

Other Side (B) = 9.45 inches

Step-by-step explanation:

Given:

Hypotenuse = 10 inches

Other Side (A) = 3.25 inches

Find:

Other Side (B) = ?

Computation:

According to Pythagoras theorem:

$Hypotenuse^2= (Perpendicular)^2+(Base)^2\\\\Hypotenuse^2= (A)^2+(B)^2\\\\10^2= (3.25)^2+(B)^2\\\\100=10.5625 +(B)^2\\\\89.4375 = (B)^2\\\\B=\sqrt{89.4375}\\\\B=9.4571$

Other Side (B) = 9.45 inches

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1.<br> Slope = (7,-1) and 12,-2)

Evgen [1.6K]

Answer: -1/5

Step-by-step explanation:

the equation to solve slope with two points is the y coordinate in the second point minus the y coordinate in the first point over the x coordinate in the second point minus the x coordinate in the first point so this one would be

(-2 - -1)/(12-7)

On the top you subtract a negative it becomes a positive and you get -1/5

6 0

3 years ago

angle A and angle B are complementary angles. If m angle A = (x-16)degrees and m angle B = (3x+28)degrees, then find the measure

Ahat [919]

Answer:

$4x \times 448$

Step-by-step explanation:

A=

$a = (x - 16)$

$b = (3x + 28)$

So you add :

$x \: and3x$

To get

$4x$

Then you do :

$16 \times 28$

To get :

$448$

Answer is :

$4x \times 448$

4 0

3 years ago

John leaves his home. He travels 5 blocks south and three blocks west. As the crow flies, how far is John from his home?

riadik2000 [5.3K]

Answer:

5.83 blocks away from his home

Step-by-step explanation:

If he travels 5 blocks south and 3 blocks west, the distance from his house considered along with the distances travelled gives a right angled triangle whose opposite side and adjacent sides are the distances travelled north and west.

The distance from his house after moving 3 blocks west is the hypotenuse side. As such, the distance may be computed using Pythagoras' theorem. Let the distance from his house be G

G^2 = 5^2 + 3^2

G^2 = 25 + 9

= 34

G = √34

=5.83

John is 5.83 blocks away from his home

3 0

3 years ago

Find the dimensions of the open rectangular box of maximum volume that can be made from a sheet of cardboard 11 in. by 7 in. by

11111nata11111 [884]

Answer:

The dimension of the open rectangular box is $8.216\times 4.216\times 1.392$ .

The volume of the box is 8.217 cubic inches.

Step-by-step explanation:

Given : The open rectangular box of maximum volume that can be made from a sheet of cardboard 11 in. by 7 in. by cutting congruent squares from the corners and folding up the sides.

To find : The dimensions and the volume of the open rectangular box ?

Solution :

Let the height be 'x'.

The length of the box is '11-2x'.

The breadth of the box is '7-2x'.

The volume of the box is $V=l\times b\times h$

$V=(11-2x)\times (7-2x)\times x$

$V=4x^3-36x^2+77x$

Derivate w.r.t x,

$V'(x)=4(3x^2)-2(36x)+77$

$V'(x)=12x^2-72x+77$

The critical point when V'(x)=0

$12x^2-72x+77=0$

Solve by quadratic formula,

$x=\frac{18+\sqrt{93}}{6},\frac{18-\sqrt{93}}{6}$

$x=4.607,1.392$

Derivate again w.r.t x,

$V''(x)=24x-72$

Now, $V''(4.607)=24(4.607)-72=38.568>0$ (+ve)

$V''(1.392)=24(1.392)-72=-38.592$ (-ve)

So, there is maximum at x=1.392.

The length of the box is $l=11-2x$

$l=11-2(1.392)=8.216$

The breadth of the box is $b=7-2x$

$b=7-2(1.392)=4.216$

The height of the box is h=1.392.

The dimension of the open rectangular box is $8.216\times 4.216\times 1.392$ .

The volume of the box is $V=l\times b\times h$

$V=8.216\times 4.216\times 1.392$

$V=48.217\ in.^3$

The volume of the box is 8.217 cubic inches.

5 0

3 years ago

Need help will mark brainliest

Tcecarenko [31]

I think it’s going to be 4/16 but I’m not a math major and I suck at math so I’m not sure

5 0

4 years ago