Question

Find the leg (in inches) of the triangle whose hypotenuse is 10 inches and whose other leg is 3.25 inches. Round to the nearest tenth. JUST ENTER THE NUMBER

Answer 1

Answer:

Other Side (B) = 9.45 inches

Step-by-step explanation:

Given:

Hypotenuse = 10 inches

Other Side (A) = 3.25 inches

Find:

Other Side (B) = ?

Computation:

According to Pythagoras theorem:

$Hypotenuse^2= (Perpendicular)^2+(Base)^2\\\\Hypotenuse^2= (A)^2+(B)^2\\\\10^2= (3.25)^2+(B)^2\\\\100=10.5625 +(B)^2\\\\89.4375 = (B)^2\\\\B=\sqrt{89.4375}\\\\B=9.4571$

Other Side (B) = 9.45 inches