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2 years ago

11

Miss Rodriguez is purchasing trophies for each child that plays Little League she wants to spend no more than seven dollars per

trophy which of the following will satisfy her budget select all that apply

1 answer:

avanturin [10]2 years ago

8 0

Answer:

c

Step-by-step explanation:

a. 3x7=21

b. 5x7=35

c. 7x7=49 [only one correct]

d. 9x7=63

e. 12x7=84

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Find the volume of each figure

Lorico [155]

Answer:

144km^3

Step-by-step explanation:

$V = (6)(6)(4)\\= 144 km^3$

7 0

1 year ago

A machine is used to fill plastic bottles with bleach. A sample of 18 bottles had a mean fill volume of 2.007 L and a standard d

abruzzese [7]

Answer:

The 99% confidence interval for the difference between the mean fill volumes at the two locations is;

-0.1175665 L < μ₁ - μ₂ < 0.1295665 L

Step-by-step explanation:

The number of bottles in the sample at the first location, n₁ = 18 bottles

The mean fill volume, $\bar{x}_{1}$ = 2.007 L

The standard deviation, σ₁ = 0.010 L

The number of bottles in the sample at the second location, n₂ = 10 bottles

The mean fill volume, $\bar{x}_{2}$ = 2.001 L

The standard deviation, σ₂ = 0.012 L

The nature of the variance of the two samples = Equal variance

The confidence interval of the statistics, C = 99%

The difference between the mean

$\mu_1 - \mu_2 = \left (\bar{x}_{1}- \bar{x}_{2} \right )\pm t_{\alpha /2} \times \sqrt{\dfrac{\sigma _{1}^{2}}{n_{1}}+\dfrac{\sigma _{2}^{2}}{n_{2}}}$

(1 - C)/2 = (1 - 0.99)/2 = 0.005, the degrees of freedom, f = n₁ - 1 = 10 - 1 = 9

∴ $t_{\alpha /2}$ = 3.25

Therefore, we have;

$\mu_1 - \mu_2 = \left (2.007- 2.001 \right )\pm 3.25 \times \sqrt{\dfrac{0.01^{2}}{18}+\dfrac{0.12^{2}}{10}}$

Therefore, we have the difference of the two means given as follows;

-0.1175665 L < μ₁ - μ₂ < 0.1295665 L

8 0

2 years ago

Rezolvati in Q ecuatiile :

Advocard [28]

What is the quasten. you did not say eny thing pasifik

4 0

2 years ago

Please answer number 3.

Alenkasestr [34]

I can't exactly SHOW you where to put the numbers, but I can teach you the process of how you'd do it.

First off, label your number line from 0-15, as it is the simplest. (You'd be counting by 1 per each line). Then, follow this process:

1) Look at the first digit of your value. Place your number according to your first digit. (So, you'd put 0.365 at the 0 line and 3.521 at the 3 line)

2) Look at the second digit of your value. Imagine that between the two main lines (0-1 and 3-4) that there is 10 smaller lines. Then, you can place your number according to your second digit. (So, you'd put 0.365 at the 0.3 line and 3.521 at the 3.5 line).

3) Look at the third digit of your value. Imagine that between the two smaller lines (0.3-0.4 and 3.5-3.6) that there is 10 smaller lines. Then, you can place your number according to your third digit. (So, you'd put 0.365 at the 0.36 line and 3.521 at the 3.52 line).

4) Look at the fourth digit of your value. Imagine that between the two even smaller lines (0.36-0.37 and 3.52-3.53) that there is 10 smaller lines. Then, you can place your number according to your fourth digit. (So you'd place 0.365 at the 0.365 line and 3.521 at the 3.521 line)

6 0

2 years ago

A 10 foot ladder is leaning against a building. It forms a 30 degree angle with the ground. How far away from the building is th

anastassius [24]

x = 8.66 ft

Step-by-step explanation:

cos 30 = adj/hyp = x/10

---> x = (10 ft)cos30

= 8.66 ft

5 0

2 years ago