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Debora [2.8K]
3 years ago
5

For a function p(x), as |x|—> infinity then p(x)—> 3. Which of the following graphs could be p(x)?

Mathematics
1 answer:
VladimirAG [237]3 years ago
7 0

Answer:

D

Step-by-step explanation:

A pe x the answer is d

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Answer:

2x...................

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Kim and her 5 friends hiked over a three day weekend hey hiked the same distance each day how many miles did they hike per day?
weeeeeb [17]
Honestly, this would depend how many miles they hiked all together. then you divide it by 3. Until you have the total amount, you don't get a correct answer. 
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4 years ago
2x^3-4xy(x+y^2) = 7y<br> y+ 25xy = 0
bagirrra123 [75]

Answer:

Answer

Step-by-step explanation:

2x^3-4xy(x+y^2) = 7y

y+ 25xy = 0

4 0
3 years ago
How do I do this? <br><br> help!!
kakasveta [241]

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Step-by-step explanation:

7 0
3 years ago
suppose that the lifetime of a transistor is a gamma random variable x with mean of 24 weeks and standard deviation of 12 weeks.
emmainna [20.7K]

The probability that the transistor will last between 12 and 24 weeks is 0.424

X= lifetime of the transistor in weeks E(X)= 24 weeks

O,= 12 weeks

The anticipated value, variance, and distribution of the random variable X were all provided to us. Finding the parameters alpha and beta is necessary before we can discover the solutions to the difficulties.

X~gamma(\alpha ,\beta)

E(X)= \alpha \beta                 \beta= 12^{2}/24=6 weeks

V(x)= \alpha \beta ^{2}                \alpha=24/6= 4

Now we can find the solutions:

The excel formula used to create Figure one is as follows:

=gammadist(X, \alpha, \beta, False)

P(12\leq X\leq 24)

P(12/6\leq G\leq 24/6)

P(2\leq G\leq 4)

P= 0.424

Therefore, probability that the transistor will last between 12 and 24 weeks is 0.424

To learn more about probability click here:

brainly.com/question/11234923

#SPJ4

4 0
1 year ago
Read 2 more answers
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