A drawer contains 12 identical white socks, 18 identical black socks

Mathematics

2 answers:

earnstyle [38]3 years ago

6 0

Answer:

2 brown

Step-by-step explanation:

The only time you can be so sure you've chosen 2 brown socks is when there are no more white socks and black socks. This means that to be 100% sure that you have chosen 2 brown socks you have to choose the 12 white socks and the 18 black socks and only then can you choose 2 brown socks without looking. Therefore, the total number of socks to choose from is:

Total number of socks = 12 white socks + 18 black socks + 2 brown socks

Total number of socks = 32 socks

A total picking of 32 socks is necessary to be sure without looking that 2 brown have already been chosen that way.

dybincka [34]3 years ago

4 0

Answer:

4 socks

Step-by-step explanation:

Lets see.

If you chose three socks, you might get 1 or white, 1 or black, and 1 of brown.

So if you chose 4, you have to get two socks of the same colour.

Hope this helps plz hit the crown :D

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Given the data points, (x, y) of a linear function: (2, 11), (4, 10), (6, 9), (12, 6), what is the function? What is the slope?

NeX [460]

Answer:

The function is $y~=~12 ~-~ 0.5 \cdot x$ .

The slope is $m=-0.5$ .

The y-intercept is $b=12$ .

Step-by-step explanation:

Our aim is to calculate the values m (slope) and b (y-intercept) in the equation of a line :

$y=mx+b$

We have the following data:

$\begin{array}{c|cccc}x&2&4&6&12\\y&11&10&9&6\end{array}$

To find the line of best fit for the points given, you must:

Step 1: Find $X\cdot Y$ and $X\cdot X$ as it was done in the table below.

Step 2: Find the sum of every column:

$\sum{X} = 24 ~,~ \sum{Y} = 36 ~,~ \sum{X \cdot Y} = 188 ~,~ \sum{X^2} = 200$

Step 3: Use the following equations to find b and m:

$\begin{aligned} b &= \frac{\sum{Y} \cdot \sum{X^2} - \sum{X} \cdot \sum{XY} }{n \cdot \sum{X^2} - \left(\sum{X}\right)^2} = \frac{ 36 \cdot 200 - 24 \cdot 188}{ 4 \cdot 200 - 24^2} \approx 12 \\ \\m &= \frac{ n \cdot \sum{XY} - \sum{X} \cdot \sum{Y}}{n \cdot \sum{X^2} - \left(\sum{X}\right)^2} = \frac{ 4 \cdot 188 - 24 \cdot 36 }{ 4 \cdot 200 - \left( 24 \right)^2} \approx -0.5\end{aligned}$